dastaten Posted July 20, 2008 Share Posted July 20, 2008 I'm using this link... <a href="view.php?id=2">link</a> to pass the "id = 2" to another page, view.php that contains this code... include 'dbconn.php'; $id = $_GET['id']; $query = "SELECT * FROM stories WHERE postid = '$id'"; $result = mysql_query($query); $page = $result['title']; echo $query . "<br /><br />"; echo $page; the echo $query writes SELECT * FROM stories WHERE postid = '2' to the page, but the $page is coming up blank. I'm still fairly new, so I have a feeling it's something easy that I'm just missing. Any help would be greatly appreciated. Link to comment https://forums.phpfreaks.com/topic/115685-can-someone-tell-me-what-im-doing-wrong-here/ Share on other sites More sharing options...
wildteen88 Posted July 20, 2008 Share Posted July 20, 2008 You need to use mysql_fetch_assoc $result = mysql_query($query); $row = mysql_fetch_assoc($result) $page= $row['title']; Link to comment https://forums.phpfreaks.com/topic/115685-can-someone-tell-me-what-im-doing-wrong-here/#findComment-594752 Share on other sites More sharing options...
dastaten Posted July 20, 2008 Author Share Posted July 20, 2008 Aaahhh, thanks so much! Link to comment https://forums.phpfreaks.com/topic/115685-can-someone-tell-me-what-im-doing-wrong-here/#findComment-594756 Share on other sites More sharing options...
unkwntech Posted July 20, 2008 Share Posted July 20, 2008 Not to mention you should use mysql_real_escape_string() to prevent people from running their own queries on you database. For more info see: http://www.php.net/manual/en/function.mysql-real-escape-string.php in preticular example #2 Link to comment https://forums.phpfreaks.com/topic/115685-can-someone-tell-me-what-im-doing-wrong-here/#findComment-594809 Share on other sites More sharing options...
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