[SOLVED] If statement doing equal to for not equal to and vice versa

[jaxdevil]

I have my database setup where EVERY cell for image_one, image_two, and image_three for every model (column `mod`) is the text 'missing'. Now what is happening is that somehow in the below code it is sending the output to not equal to 'missing', when they are equal to missing. What could this be?

 

<?php
if ( $medical == "Product")  {
?>
<?
$images_query = "SELECT * FROM `images` WHERE `mod` = '$code' LIMIT 1";
$images_result = mysql_query($images_query) or die(mysql_error());
while($row = mysql_fetch_array($images_result)) {
if ( $image_one != "missing")  {
$image_one = "/prod_images/".$code."/".$row['image_one'].".jpg";
}
if ( $image_one == "missing")  {
$image_one = "/prod_images/missing.jpg";
}
if ( $image_two != "missing")  {
$image_two = "/prod_images/".$code."/".$row['image_two'].".jpg";
}
if ( $image_two == "missing")  {
$image_two = "/prod_images/missing.jpg";
}
if ( $image_three != "missing")  {
$image_three = "/prod_images/".$code."/".$row['image_three'].".jpg";
}
if ( $image_three == "missing")  {
$image_three = "/prod_images/missing.jpg";
}
$image_mod = $row['mod'];
?>

[GingerRobot]

$image_one is undefined. You need to use $row['image_one'].

[jaxdevil]

That was it man, I appreciate your help greatly! Thanks a million!

 

SK