[SOLVED] php date

[dg]

hi ........all

  i have the day of the year and year, how to convert it to date format (dd/mm/yyyy) in php

 

 

thanx

dg

[ignace]

date("d-m-Y", mktime($hour, $minute, $second, $day, $year, $month));

 

 

mktime() reference: http://be.php.net/manual/en/function.mktime.php

date() reference: http://be.php.net/manual/en/function.date.php

[LemonInflux]

Wouldn't

date('d/m/y')

work?

 

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[dg]

hi

i m not finding the current date .....

i have the year day (that is if it is 2nd jan than i hav 1 as year day)

and the year ....

for example

year_day = 1

year = 2008

 

so i want function which returns 02/01/2008

 

thanx

[LemonInflux]

Hang on, so show us the input you have? If you have '29', '6', '93', surely all you need is implode()?

 

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[dg]

hi .....

i have "z" option of date();

so i have the year day and also year

year_day = 364 <------------- this will be 31st decmember

and year = 2008

 

so using year_day n year .... i need the output to be 31/12/2008

 

hope now it is clear

[Barand]

<?php
$dayOfYear = 364;
$year = 2008;
echo date ('d/m/Y', strtotime ("+$dayOfYear days $year-01-01"));
?>

[dg]

thanx for the reply ........... it's working

[Barand]

date("d-m-Y", mktime($hour, $minute, $second, $day, $year, $month));

 

@ignace

your args are in the wrong order. See

 

mktime() reference: http://be.php.net/manual/en/function.mktime.php

 

So this would do it too

echo date("d-m-Y", mktime(0, 0, 0, 1, $dayOfYear+1, $year));