ngreenwood6 Posted July 31, 2008 Share Posted July 31, 2008 I am trying to display all of the variables under a table row. my code is: <?php //include the variables include ("variables.php"); include ("db.php"); $getfrom_db = "SELECT email FROM users"; //connect to database $mysqli_connect = mysqli_connect($host,$db_user,$db_pass,$db_name) or die ("Could not connect to database"); //variable to get data to the database $result = mysqli_query($mysqli_connect,$getfrom_db) or die ("Error: ".mysqli_error($mysqli_connect)); //get the data and pull it $info = mysqli_fetch_array($result); //used for the connection to get email addresses from database $email = $info['email']; if (!$info) { echo ("No Data"); } else { echo ("$email"); } ?> The echo statement at the bottom is supposed to display all of the emails but it is only displaying the first one in the database. Does anyone have any idea how to display more than one database object. Quote Link to comment Share on other sites More sharing options...
MaaSTaaR Posted August 1, 2008 Share Posted August 1, 2008 Hello ... use "while" to get all results : while ($info = mysqli_fetch_array($result)) { echo $info['email'] . '<br />'; } Quote Link to comment Share on other sites More sharing options...
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