rnintulsa Posted August 3, 2008 Author Share Posted August 3, 2008 Ok, I replaced it. if( $num_rows > 0 ) { $_SESSION['username'] = $username; //redirect $data = mysql_fetch_array($results); $company = $data['company']; echo "$company"; header("Location: {$data['company']}.php"); } else { header("Location: login_error.htm"); } and am getting these errors: SELECT * FROM access WHERE username='terryf' and company = 'southern' Notice: Undefined variable: results in /nfs/cust/4/45/65/556544/web/run_login_access.php on line 41 Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /nfs/cust/4/45/65/556544/web/run_login_access.php on line 41 Warning: Cannot modify header information - headers already sent by (output started at /nfs/cust/4/45/65/556544/web/run_login_access.php:29) in /nfs/cust/4/45/65/556544/web/run_login_access.php on line 44 Quote Link to comment https://forums.phpfreaks.com/topic/117938-solved-taking-my-login-a-step-further/page/2/#findComment-606736 Share on other sites More sharing options...
rnintulsa Posted August 3, 2008 Author Share Posted August 3, 2008 Well, this has gotten long and complicated (not for you all probably) for me. The greatly appreciated person that was helping me is no longer online, so I am going to hit solved since my initial question was solved, and work on this a while on my own. Thanks to all who contributed. Quote Link to comment https://forums.phpfreaks.com/topic/117938-solved-taking-my-login-a-step-further/page/2/#findComment-606749 Share on other sites More sharing options...
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