GD imagejpeg(); issues

[bothwell]

Caveat: I've never used GD before, so I have absolutely no idea what I'm doing.

 

Warning: imagejpeg(): supplied argument is not a valid Image resource in C:\htdocs\admincp\test.php on line 30

 

The above always appears at the top of the page

 

The database record contains always contains "1." when I POST using this code:

 

      foreach ($_FILES as $file)
        {
          if ($file['error'] == UPLOAD_ERR_OK)
            {
              $jpg = imagejpeg ($file);
              
              $tmp_name = $jpg['tmp_name'];
              $name = $jpg['name'];
              $fileNameParts = explode( '.', $name );
              $target = "../images/properties/$name";
              while (file_exists($target))
              {
                $fileNameParts[0] .= "1";
                $name = $fileNameParts[0] . "." . $fileNameParts[1];
                $target = "../images/properties/$name";
              }
              move_uploaded_file($tmp_name, $target);

              $dbUpdate = "UPDATE images2 SET images='$name' WHERE image_id=$id";
              mysql_query($dbUpdate) or die(mysql_error());
            }	
        }

 

Line 30 is the $jpg = imagejpeg ($file); bit just underneath UPLOAD_ERR_OK

 

Like I say, I have no idea what I'm doing here. Any pointers as to what's expected of imagejpeg(); would be appreciated

 

[cooldude832]

look at how imagejpeg works you must have a valid image resource meaning you can't stream a file unless you first use imagejpegfromfile or imagejpegfromstring or what ever they are called.

[ignace]

// multiple uploads are added in a numerical array as explained in the php manual 
// $_FILES = array
// (
//     'tmp_name' => array('msdj.tmp', 'msjsd.tmp', ...),
//     'name' => array('filename1', 'filename2', ...),
//     'size' => array('sizeFile1', 'sizeFile2', ..),
//     ...
// );
// 
// number of uploads
$num_uploads = sizeof((array) $_FILES['tmp_name']);

if (1 < $num_uploads) { // multiple uploads
   for ($i = 0; $i < $num_uploads; $i++) {
       if ($_FILES['error'][$i] == UPLOAD_ERR_OK) {
           // this upload is ok
       }
    }
}// Else single upload

[bothwell]

look at how imagejpeg works you must have a valid image resource meaning you can't stream a file unless you first use imagejpegfromfile or imagejpegfromstring or what ever they are called.

 

Ah, gotcha. Couldn't figure out if it was ok to try and convert directly from POST or not - but seems not. Looks like it's all working now, so thanks!