array_splice not working correctly?

[critical-state]

Hi, hoping somone can shed some light on a problem I am having when using an array_splice to remove elements from an array.

I am new to php so maybe my approach or method is wrong?

I am trying to ensure that when a user selects from a <option> list of drinks </option> the drink selected is displayed within the form but not duplicated.

 

oridinally it worked as expected. However I temporaly changed part of my array and when I put it back it no longer works as it should on my system.

I have even tried creating new arrays but am still having the same problem with the first element of any array that I create.  Am I doing somthing wrong is there a way to reset the array to work as it oridinally did?

 

<?php

 

error_reporting(E_ALL);

//define varables:

$d_color=0;

$drinks=array("guiness","larger","beer","vodka","gin");

if(!isset($_POST['drink'])){$_POST['drink']="Choose One" ; $d_color="black";}

if($_POST['drink']=="guiness"){array_splice($drinks,-4);}/* When I run the code for some reason it shows up as guiness, guiness with no other drinks listed? it should show all drinks except guiness. although guiness will show as it is retained and displayed by the echo $_POST['drinks'] array*/

if($_POST['drink']=="larger"){array_splice($drinks,1,-3);}// this works as expected no duplication of larger

if($_POST['drink']=="beer"){array_splice($drinks,2,-2);}//this works as expected

if($_POST['drink']=="vodka"){array_splice($drinks,3,-1);}// this works as expected                                                                 

if($_POST['drink']=="gin"){array_splice($drinks,4);}//this works as expected       

 

 

?>

<form method="post" action="">

<?php echo"<font color=\"$d_color\">Choose Drink</font>";?><select style="display:block;" name="drink">

 

<option><?php echo $_POST['drink'];?></option>

<?php

foreach($drinks as $drink){

echo "<option>" .$drink ."</option>";

}

?>

 

</select>

 

<input type ="submit" value ="go">

</form>

[odisey]

I read your post, and I really am not sure what the problem is by what you have said.  You do not what something selected duplicated?  Can you be more specific?

 

I will try.

 

Odisey

[critical-state]

Ok I will try and explain better.

 

Had I not used the array_splice and run the script and chose for example "gin". I would be getting):

gin as my choice in the display field. If I then go to re-select I would get:

gin

gin

guiness

larger

beer

vodka

 

I dont want this duplication so I use array_splice

 

I run the script choose for example "gin" my script is working correctly and displaying:

gin as my choice in the display field.  If I then go to re-select I get:

gin

guiness

larger

beer

vodka.

This is all working correct.

 

All drinks are working as expected ie no duplication when re-selecting except guiness.

if I run the script and choose guiness, I get:

guiness for my choice and then if I re-select I get:

guiness

guiness

 

 

As I said this was oridinally all working correctly until I temporary changed my array_splice and $drinks array. Its seems that some how I have effected the arrays position in some form and it needs re-setting some how.

If I change this:

if($_POST['drink']=="guiness"){array_splice($drinks,-4);}

to this

if($_POST['drink']=="guiness"){array_splice($drinks,-2);}

 

it should then be showing only the last two drinks in the array. However it shows on my machine the following:

 

guiness (selected)

guiness

guiness

larger

beer

 

It's as though it is working in a reverse order ?????????

I am baffled  ???

Please help

 

Andy