Canman2005 Posted June 13, 2006 Share Posted June 13, 2006 Hi allI have the following script which takes an image and rotates it,[code]$filename = 'images/help.jpg';$degrees = 350;$source = imagecreatefromjpeg($filename);imagecolortransparent($source,imagecolorat($source,0,0)); $rotate = imagerotate($source, $degrees, 0);$quality=100;$image = imagejpeg($rotate,"",$quality);[/code]The problem is that im left with a black background and I cannot seem to turn the background transparent.Can anyone help?Thanks in advanceEd Quote Link to comment https://forums.phpfreaks.com/topic/11826-php-image-rotation-question/ Share on other sites More sharing options...
poirot Posted June 13, 2006 Share Posted June 13, 2006 imagerotate()'s third parameter defines the background color:[!--quoteo--][div class=\'quotetop\']QUOTE[/div][div class=\'quotemain\'][!--quotec--]resource imagerotate ( resource src_im, float angle, int bgd_color )[/quote][a href=\"http://www.php.net/imagerotate\" target=\"_blank\"]http://www.php.net/imagerotate[/a] Quote Link to comment https://forums.phpfreaks.com/topic/11826-php-image-rotation-question/#findComment-44805 Share on other sites More sharing options...
Canman2005 Posted June 13, 2006 Author Share Posted June 13, 2006 Hiso what background value keeps it transparent?Thanks Quote Link to comment https://forums.phpfreaks.com/topic/11826-php-image-rotation-question/#findComment-44813 Share on other sites More sharing options...
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