stbalaji2u Posted August 12, 2008 Share Posted August 12, 2008 I executed this smalllllll calculator program in php and when i cleared all my errors and again tried to execute in a browser but the firefox says that the ""Connection Interrupted The connection to the server was reset while the page was loading The network link was interrupted while negotiating a connection. Please try again."" i used a calc.html page to create form and passed the value using the post method what the hell is wrong with my code.. :'( this is calc.html's code <html> <Title>Calculator</Title> <body> <form name=calc action='calc.php' method='post'> <table border =0 cellspacing =3 cellpadding=2> <tr><td colspan=4 align=center> <h3>Calculator</h3> <tr><td> <input type=text name=num1> <td> <select name=func> <option value=add>+</option> <option value=sub>-</option> <option value=mul>*</option> <option value=div>/</option> </select> <td> <input type=text name=num2> <td> <input type=submit name=submit value="Go!" > </table> </form> </body> </html> and this is calc.php's code <?php $num1=$_POST[num1]; $num2=$_POST[num2]; $func=$_POST[func]; $submit=$_POST[submit]; if($submit==false){ include('calc.php'); } else if($func==add){ include('form.php'); $num3=$num1 + $num2; echo "<b>Solution</b>"; echo "<br>"; echo "$num1 + $num2 = $num3"; } else if($func==sub){ include('calc.php'); $num3=$num1 - $num2; echo "<b>Solution</b>"; echo "<br>"; echo "$num1 - $num2 = $num3"; } else if($func==mul){ include('calc.php'); $num3=$num1*$num2; echo "<b>Solution</b>"; echo "<br>"; echo "$num1 * $num2 = $num3"; } else if($func==div){ include('calc.php'); $num3=$num1/$num2; echo "<b>Solution</b>"; echo "<br>"; echo "$num1 / $num2 = $num3"; } ?> Link to comment https://forums.phpfreaks.com/topic/119316-solved-problem-with-calcphp-program/ Share on other sites More sharing options...
wildteen88 Posted August 12, 2008 Share Posted August 12, 2008 The form submits to calc.php, however in calc.php you include calc.php! Whats that about? Doing that could cause an infinity loop and thus the error you get. EDIT: This is how I'd do it: <?php if(isset($_POST['submit'])) { $num1 = $_POST['num1']; $num2 = $_POST['num2']; switch($_POST['func']) { case 'sub': $num3 = $num1 - $num2; $sum = "$num1 - $num2 = $num3"; break; case 'mul': $num3 = $num1 * $num2; $sum = "$num1 * $num2 = $num3"; break; case 'div': $num3 = $num1 / $num2; $sum = "$num1 / $num2 = $num3"; break; case 'add': default: $num3 = $num1 + $num2; $sum = "$num1 + $num2 = $num3"; break; } echo "<b>Solution</b>"; echo "<br>"; echo $sum . '<hr />'; } include 'calc.html'; ?> Link to comment https://forums.phpfreaks.com/topic/119316-solved-problem-with-calcphp-program/#findComment-614621 Share on other sites More sharing options...
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