check if...

[abs0lut]

<?php 
session_start();
include 'conn.php';
$post = $_GET['post'];
$slected = array();
if(isset($_POST['checkb'])){
if(count($_POST['cid']) > 0){			
	foreach($_POST['cid'] as $awrd) {
	$result = mysql_query("UPDATE ctable SET award='yes' WHERE id='$awrd'") or die(mysql_error());
	$slected[] = $awrd;
    		}		
}			
} else{

?>   
<form method="post" name="formk" action="<?= $_SERVER['PHP_SELF']. '?' . $_SERVER['QUERY_STRING'] ?>">
<?php
$result = mysql_query("SELECT cid, iqid, cost, usersid FROM ctable WHERE post=$post");
while ($row = mysql_fetch_array($result))
{
  $arr[$row['iqid']][$row['usersid']] = $row['cost'];
  $arr2[$row['iqid']][$row['usersid']] = $row['cid'];
  $uid[] = $row['usersid'];
}
$uid = array_unique($uid);
$qid = array_keys($arr);

echo '<table><tr><td></td>';
foreach($uid as $userid) echo "<td>$userid</td>";
echo '</tr>';
foreach($qid as $iqid)
{
  echo "<tr><td>$iqid</td>";
  foreach($uid as $userid)
  {
    if (isset($arr[$iqid][$userid]))
    {       
	echo "<td>".$arr[$iqid][$userid]."<input type='checkbox' name='cid[]' value='{$arr2[$iqid][$userid]}'></td>";	
}
else echo "<td></td>";	
  }
  echo "</tr>";
}
echo '</table>';
echo '<input type="submit" name="checkb" />';
echo'</form>';	

}
?>

I need to check if the $iqid of $arr2[$iqid][$userid] is equal to other, could you please help me?

[budimir]

if ($iqid == $arr2[$iqid][$userid]){

continue with your code....

}

[abs0lut]

please read my code...

[abs0lut]

http://img179.imageshack.us/my.php?image=cb3gh2.jpg

 

I need to display an error message "you have checked same iqid",

when the users checks 2 or more cost in iqid1

when the users checks 2 or more cost in iqid2

and so on..

 

please help me...