weby Posted August 18, 2008 Share Posted August 18, 2008 This looks like a forum with a lot of knowledge, hope you can help me with my issue or point me in the right direction.. I'm trying to search for a login name that fits to either one of 3 search terms: login (username), email or distributornr. I have 2 tables amember_members and profile with the members_id being the same in both tables. The search comes from a form with one field name search so thats the variable $search My code looks like this: $sql="SELECT amember_members.login, amember_members.email, profile.distributornr FROM amember_members LEFT JOIN profile ON amember_members.member_id = profile.member_id WHERE login LIKE '$search' OR distributornr LIKE '$search' OR email LIKE '$search'"; $rs=mysql_query($sql) or die(mysql_error()); $num=mysql_num_rows($rs); This is the error message I get. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'login LIKE 'test' OR distributornr LIKE 'test' OR email LIKE 'test'' at line 1 Maybe it's easier then I think to solve this.. but I've tried with various ways of coding.. and I just cant get it right. Let me know if you need more info. Quote Link to comment Share on other sites More sharing options...
toplay Posted August 18, 2008 Share Posted August 18, 2008 Don't forget the percent signs. Try something like this: $sql="SELECT m.login, m.email, p.distributornr FROM `amember_members` m LEFT JOIN `profile` p USING (member_id) WHERE m.login LIKE '%$search%' OR p.distributornr LIKE '%$search%' OR m.email LIKE '%$search%'"; Quote Link to comment Share on other sites More sharing options...
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