[SOLVED] Help With If Statement Syntax

[webref.eu]

Hi All

 

I have to code an statement that says "If not the conditions where processform is 1 AND ErrorMsg is empty string".  So far I have this: 

 

If !($_POST['processform'] == 1 AND ErrorMsg == "") {

 

which I know is wrong.  Can anyone help me correct it?

 

Thanks All.

[waynew]

What about:

 

If ($_POST['processform'] != 1 && ErrorMsg == "") {

[Mchl]

If ($_POST['processform'] != 1 || ErrorMsg != "") {

 

AND => &&

OR => ||

 

waynewex: de Moragn's laws apply

[waynew]

Sorry didn't focus on logic. Just seen the script and corrected it without reading what he had said.

 

[Mchl]

Sorry didn't focus on logic. Just seen the script and corrected it without reading what he had said.

 

webref.eu:

syntax in general is:

if (condition) {

}

 

condition is always in () parentheses

[webref.eu]

Guys, I still don't think I have this right.  Let me explain further: 

 

Under these conditions: 

 

$_POST['processform'] == 1

AND

ErrorMsg == ""

 

I don't want a form to be displayed, so I have to write and If statement saying If Not both the above mentioned conditions.  If think it's something like: 

 

If !(($_POST['processform'] == 1) && (ErrorMsg == "")) {

 

but this still isn't quite right as I'm getting an unexpected ! error. 

 

Thanks all.

[Mchl]

condition is always in () parentheses

 

If ($_POST['processform'] != 1) && (ErrorMsg != "") {

or

If (!($_POST['processform'] == 1 || ErrorMsg == "")) {

 

 

Besides, I believe ErrorMsg is a variable so: $ErrorMsg

[webref.eu]

Thanks for your help with the logic statement.  Here is the code that I have found to work the way I wanted regarding when to display the form: 

 

<?php
If (!($_POST['processform'] == 1 && $ErrorMsg == "")) {
?>

<!-- display the form -->
<form> ... </form>

<?php
//end if
}
?>

 

Rgds