Issue(?) Calling General AJAX Function Multiple Times

[FoolishOne]

This is killing me and I am hoping you guys can help.

 

I am using SACK as my 'framework' for this little AJAX side project of mine. Anyone familiar?

 

I have two (2) select boxes.  For this test, all I want is to get what the user selected in the select box, with the potential to do a whole bunch with it later (formatting, changing the text, etc.)

 

The first box is full of all 50 states.  The function below gets 'state' and 'Texas', and works PERFECTLY. (format-state only has an echo statement in it.)

 

Code:

function sack_display(section,value)
{
        alert("in sackdisplay with "+section+" & "+value);
ajax.setVar(section, document.getElementById("select-"+section).value);
ajax.requestFile = "format-"+section+".php";  // format-state...check
ajax.method = "POST";
ajax.element = section+"-content";  //state-content...check
ajax.onLoading = whenLoading;
ajax.onLoaded = whenLoaded; 
ajax.onInteractive = whenInteractive;
ajax.runAJAX();
}

 

Now, I call it again from a different select box (full of counties)

 

<.... onchange="sack_display('county','Harris County');">

 

And it doesn't budge. I change the county and the alert doesn't show up, nothing.  All the HTML elements are there and visible.  If I copy the function and call it display2, and call display 2 from the county select, it works perfectly.  I don't want to have a different function for every option box.

 

Everything appreciated.

 

Thanks!

[bluebutterflyofyourmind]

I've run into a similar issue and would really appreciate some help as well.

[FoolishOne]

After beating everything out of it I could, I believe that I may have solved my own problem.  I can attribute some of my problem to not completely refreshing everything.

 

I am going to try and apply it to a couple other form elements and see if the general function works for more than the 2 of the elements I have it working for currently.

[bluebutterflyofyourmind]

how did you solve your problem?

 

[FoolishOne]

I double-checked my code on my end, deleted everything remotely involved in the function/call on the server side, re-uploaded everything, and did a forced/hard refresh. My issue involved not refreshing, 2 functions named the same thing , and not properly escaping quotes in the PHP. (Kinda inexperienced at JS, but I noticed that if there is even one error in the JS file, NOTHING will work. My solution was to double click on it in windows explorer. I didn't have anything program associated with it, so it would try and run it, and hence debug it for me.)

 

For people searching later, I believe you can in fact call the function doing the AJAX as many times as you want. It was a 'user error'.

 

In a position like this, the first thing I do/did was put an alert("in here"); or something like that as the first line in the function. If I didn't get a pop-up when I was supposed to, I knew that I couldn't even begin to look at the JS, because it wasn't even getting there. I would check the call in the HTML, and go on from there.

 

Is there a section of code you want to post up?