[SOLVED] Find if hostname is a domain or IP

[53329]

Hi,

 

I've found a few php scripts that can properly get the hostname from a url (most of the time...) but they always seem to fail if its an IP.  They keep cutting off the first octet thinking that it is a subdomain.

 

It sounds simple but for some reason I can't figure out how to tell if the url I have is a domain name like:

http://subdomain.example.com/index.php

or if it's just an IP like:

http://72.14.207.99/index.php

 

If I could determine that a url is an IP it would save me so much time.  Either finding out how to do that or a php script that actually parses URLs well would solve all of my problems.

[effigy]

Do you want to match both, or just IPs (see below)?

 

<pre>
<?php
$data = <<<DATA
http://subdomain.example.com/index.php
or if it's just an IP like:
http://72.14.207.99/index.php
DATA;
preg_match_all('%http://[\d.]+\S+(?<!\p{P})%', $data, $matches);
print_r($matches);
?>
</pre>

[nrg_alpha]

You can do a crude format check...

 

$str = 'http://72.14.207.99/index.php';
// $str = 'http://subdomain.example.com/index.php'; // uncomment this line and comment the line above to test the other way around...
echo (preg_match('#http://[0-9]+(\.[0-9]+)+/#', $str))? 'true' : 'false';

 

While this pattern doesn't check to see if the IP is a valid formatted one, it does check to see if it is an IP format (of some sort).

 

 

[53329]

Thanks a lot.  I'll use the second one simply because a true/false works better in this scenario.  I was using it to referer block the domains of common hotlinkers.  If it's an IP I just loose the http and everything after the first forward slash.  If it's not I run it through my other script.  Works like a charm 

[53329]

Actually I may as well see if there is a fix for this because it would save a lot of time. I played around with it and made the IP regex a little more refined.

 

If I get a match for IP how do I omit the line for the host, subdomain and domain? As is I can only get one or the other to work by alternating commented lines.

 

$url = 'http://72.14.207.99:80/index.php?test=1#2';
//$url = 'http://subdomain.example.com/index.php';

$r  = "^(??P<scheme>\w+)://)?";
$r .= "(??P<login>\w+)?P<pass>\w+)@)?";
$r.="(??P<ip>(([0-9]{1,3}+\.){3}+[0-9]{1,3})))?";
//$r .= "(?P<host>(??P<subdomain>[-\w\.]+)\.)?" . "(?P<domain>[-\w]+\.(?P<extension>\w+)))";
$r .= "(?:?P<port>\d+))?";
$r .= "(?P<path>[\w/]*/(?P<file>\w+(?:\.\w+)?)?)?";
$r .= "(?:\?(?P<arg>[\w=&]+))?";
$r .= "(?:#(?P<anchor>\w+))?";
$r = "!$r!";	// Delimiters
preg_match($r, $url,$parsed);
print_r($parsed);

[nrg_alpha]

That's quite the mind boggling expression you have going there.. 

As far as being able to determine if it is an IP based url or not, could you not do something a little more simple?

 

//$str = 'http://72.14.207.99/index.php';
$str = 'http://subdomain.example.com/index.php';
if(preg_match('#http://([0-9]+(\.[0-9]+)+)/#', $str, $match)){
   // IP address detected...
   echo $match[1]; // your isolated IP address.. do what you will with it..
} else {
   // Non IP URL found instead...
   echo 'Non IP URL detected';
}

 

 

[53329]

Well I can grap the IP no problem now.  Its combing it with my url parsing script that is the problem.

 

Put simply I need a way for backrefrence "host" not to match anything if the backrefrence "ip" does.  If I can find regex to do that I can probably work it in.

[53329]

Fixed.  Here is the code for anyone who wants it.  It should parse any url conceivable (I stress should).

 

//$str = 'http://72.14.256.99:80/index.php?test=1#2';
$str = 'http://subdomain.example.com/index.php';

$r  = "^(??P<scheme>\w+)://)?";
$r .= "(??P<login>\w+)?P<pass>\w+)@)?";

$ip="(?:[0-9]{1,3}+\.){3}+[0-9]{1,3}";//checks for ip
$not_ip="(?P<subdomain>[-\w\.]+)\.)?(?P<domain>[-\w]+\.(?P<extension>\w+))";//always works so we need a conditional

$r.="(?P<host>(?(?=" . $ip . ")(?P<ip>" . $ip . ")|(?:" . $not_ip . "))";

$r .= "(?:?P<port>\d+))?";
$r .= "(?P<path>[\w/]*/(?P<file>\w+(?:\.\w+)?)?)?";
$r .= "(?:\?(?P<arg>[\w=&]+))?";
$r .= "(?:#(?P<anchor>\w+))?";
$r = "!$r!";	// Delimiters
preg_match($r, $str,$parsed);
print_r($parsed);
if($parsed['ip'])
{
if(long2ip(ip2long($parsed['ip']))==$parsed['ip'])
	{
	echo "<br />Valid IP";
	}
else
	{
	echo "<br />Invalid IP";
	}
}
if($parsed['domain'])
{
//not an ip
}

 

Thanks nrf_alpha and effigy.

[angelfashion]

fiuh finally found this solution hehe