kevinak Posted September 10, 2008 Share Posted September 10, 2008 Hello. I have a query that checks for pet IDs based off a user's id. It generates a table with all the ones that it finds with this code //checks if any results are returned if (mysql_num_rows($resultpets) > 0) { //sets up my table echo"<table border=1 width=500>"; //For each pet id found, it will add a column while($row = mysql_fetch_row($resultpets)) { echo "<tr><td><center><img src=http://whimpsters.net/pets.php/".$row[0]." style='border-style: none'><input type=checkbox name=".$petname[$row]." value=".$row[0]." /></td>"; //4 more columns to make 5 column rows The key point to this being... <input type=checkbox name=".$petname[$row]." value=".$row[0]." /> Now I have the checkbox's name to equal the array $petname[petid] and the value is just the pet id number. Now, using a for each loop, how can I check which check boxes have been marked? Would it be anything like this foreach($petname as $key => $value) { if(isset($key)) { //do stuff for checked boxes } } Link to comment https://forums.phpfreaks.com/topic/123635-checking-checkboxes-in-a-generated-table/ Share on other sites More sharing options...
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