[SOLVED] Error with class/php file..

[dity]

I'm trying to implement a class file so I don't have to duplicate a lot of code, anyways I keep getting this syntax error and I'm pulling my hair out trying to figure out why..

 

Parse error: syntax error, unexpected T_STRING, expecting T_OLD_FUNCTION or T_FUNCTION or T_VAR or '}' in /ActiveUser.class.php on line 5

 

Here is my ActiveUser.class.php code..

<?php
class ActiveUser
{

public function __construct()
{
}

public function count($username, $password = null, $link = null)
{
$sql = "SELECT COUNT(*) FROM active_user WHERE username = ".mysql_real_escape_string($username)."";

if (!empty($password))
{
$sql .= " AND password = ".md5($password)."";
}

$query = $this->query($sql,$link);

return mysql_result($query, 0, 0);
}

public function insert($username, $password, $link)
{
$sql = "INSERT INTO active_user VALUES (”,".$username.", ".md5($password).")";
$query = $this->query($sql, $link);
}

private function query($sql, $link)
{
$query = mysql_query($sql,$link);

if (!$query)
{
return "problem with sql, ".mysql_error();
}

else
{
return $query;
}

}
}
?>

 

 

[wildteen88]

What version of PHP are you using? You should not be having any problems if you're using PHP5 . However you will get that error with PHP4.

 

PHP4 has very limited OOP support. PHP4 does not support visibility keywords (public, private, protected) nor does it support magic function such as __construct

[dity]

im using php 5..

[dity]

has anyone else ran into this problem?

[waynew]

Try

 

<?php
class ActiveUser
{

public function ActiveUser()
{
}

public function count($username, $password = null, $link = null)
{
$sql = "SELECT COUNT(*) FROM active_user WHERE username = ".mysql_real_escape_string($username)."";

if (!empty($password))
{
$sql .= " AND password = ".md5($password)."";
}

$query = $this->query($sql,$link);

return mysql_result($query, 0, 0);
}

public function insert($username, $password, $link)
{
$sql = "INSERT INTO active_user VALUES (”,".$username.", ".md5($password).")";
$query = $this->query($sql, $link);
}

private function query($sql, $link)
{
$query = mysql_query($sql,$link);

if (!$query)
{
return "problem with sql, ".mysql_error();
}

else
{
return $query;
}

}
}
?>

[discomatt]

The script executes without error on PHP 5.2.6/Apache 2.2.8 and error_reporting( E_ALL ).

 

Are you SURE you have PHP5?

 

Try executing phpinfo(); It'll tell you right at the top.

[dity]

My host is retarded..  you have to rename your php files to .php5 if you want them on php 5.. thanks problem solved..