Using PHP to display an image

[calrockx]

I set a DIV class's background property to use a php file as the background image.

 

The problem is, I can't get that php file to display an image.  Enter that php file name directly to the browser and it should simply show an image, not any code.

 

My question is, how do I do that? How do I make a php page render to show an image?

I know the header is involved, but some attemps to make that happen didn't work out so well.  What I want to do is put an if...else statement in there so that depending on the $_GET value, that php file will display one of a number of images.

 

Can anyone spell out in a quick few lines of code just the format to get an image showing and then I can try to work it from there?

[CroNiX]

Best to post the code you have.

[The Little Guy]

how are you typing the URL into the address bar?

[calrockx]

Oh I don't have much going right now.  I guess I can post the if-else statement I have going..

 

if(!$_GET[image]) {
		echo '/sections/_other/image.php/?width=600&height=450&&image=/sections/residential/_cover/cover.jpg'; } 
	else {
		echo '/sections/_other/image.php/?width=600&height=450&&image=/sections/'.$_GET[section].'/'.$_GET[category].'/'.$_GET[image].''; } 

    }

 

Those GET varaibles are based on what the user clicks on the website.

I just need to know how to get it to output an image.  For example, I use this rotator script on another site, and when you go to it in the browser, it just shows you an image - http://cultural-distiller.com/_images/global/backgrounds/main/rotator.php

 

 

I tried looking at that code for some clues, but it's beyond me.