Jump to content

Need help with setting a position


NathanLedet

Recommended Posts

I'm working on a small CMS and I've been following the tutorials at Lynda.com.

 

When I'm on the page to Add a Page, I want to set its position (the order), so I have a drop down list which counts the number of records inside the database, and then adds 1 (if I have 3 entries, I want "4" to be highlighted so it will automatically be put in the last position)

 

The code I currently have will count the rows, and then select the position it's currently in:

 

$page_count = mysql_num_rows($page_set);

for($count=1; $count <= $page_count+1; $count++){
echo "<option value=\"{$count}\"";
	if ($sel_page['position'] == $count){
		echo " selected";
		}
			echo ">{$count}</option>";
	}

 

I want to modify that code so that when I'm adding a new entry, it automatically chooses the last available option.

 

Thanks for the help :)

Link to comment
Share on other sites

Where is your $sel_page['position'] variable being set?

It's set elsewhere in the page and returns a number from the database. that number is the position: 1, 2, 3 etc.

 

 

Also, why not just do this:

	

if (($page_count+1) == $count){
echo " selected";
}

 

 

I dunno... Ask Kevin Skoglund...I'm following his lessons.  :)

 

 

Link to comment
Share on other sites

Yes let me gather it up. 

 

but I don't think I was clear enough - sorry about that. 

 

The code I posted does work.  It works whenever I EDIT the page.  It properly displays the selected position.

 

What I am trying to do is re-structure that code that I already have and make it so that when I'm ADDING a page, it automatically chooses the last available position.  So, if I have 3 pages, I want that script to display and have already selected "4" in the drop down menu.

 

 

Link to comment
Share on other sites

functions.php

function get_all_pages(){
global $conn;
$query = "SELECT * FROM pages ORDER BY position ASC";
$page_set = mysql_query($query, $conn);
confirm_query($page_set);
return $page_set;	
}

 

add_page.php - Form

$page_set = get_all_pages();
$page_count = mysql_num_rows($page_set);
for($count=1; $count <= $page_count+1; $count++){
echo "<option value=\"{$count}\">{$count}</option>";
}

 

Link to comment
Share on other sites

You're still not showing where $sel_page is set. I suggest you check to see if that is set or not. If it is not, default to $page_count+1 rather than $sel_page['position']. But, I don't know your code for setting that, so I can't help you with that part without seeing it.

Link to comment
Share on other sites

OK... tinkered around with the code a little bit and this code here works.  I appreciate you help F1Fan, and I apologize for not being clear.  My original code in my first post had nothing to do with the result, and therefore $sel_page makes no difference

 

for($count=1; $count <= $page_count+1; $count++){
echo "<option value=\"{$count}\" ";
if ($count == $page_count+1){
		echo " selected=\"selected\"";
		}
		echo ">{$count}</option>";
}

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.