[SOLVED] define a variable to a float type

[Voodoo Jai]

Hi again all

I have 2 variables that I take from my database that are of the type FLOAT what I want to do is add them together to give a FLOAT value.

My problem is that I want it to show the figures after the decimal point even if they are ZERO figures.

 

<?php 
$ListFee = "58.00";
$BorderFee = "12.00";

$TotalAmount = ($ListFee + $BorderFee);

echo $TotalAmount;
?>

 

the output gives me 70

I want 70.00

 

Many thanks in advance again

VoodooJai

[nadeemshafi9]

do a search for float or something in the php manual

[mursalat]

just add a .00 to it when you echo it, php only gives to decimal places if there is any value in decimal places.

[thebadbad]

<?php
echo round($TotalAmount, 2);
?>

 

Edit: Sorry, doesn't work. This should:

 

<?php 
echo number_format($TotalAmount, 2, '.', '');
?>

 

Uses a dot for decimal point, and nothing for thousands separator.

[Voodoo Jai]

<?php
echo round($TotalAmount, 2);
?>

 

This still does not give me the ZERO's after the INT didgits.

 

Have looked at the PHP manual but don't understand what I am looking for exactly.

 

Cheers all.

[Voodoo Jai]

Got it eventually thanks all

$ListFee = 58.00;
$BorderFee = 12.00;
$TotalAmount = $ListFee + $BorderFee;
$Amount = printf("%01.2f", $TotalAmount);

[thebadbad]

Guess you didn't notice my edit

[nadeemshafi9]

thats not the proper way to do it, you need to specify decimal percission

[thebadbad]

thats not the proper way to do it, you need to specify decimal percission

 

Agree, he should use number_format() like I suggested.