ngreenwood6 Posted October 5, 2008 Share Posted October 5, 2008 I am in need of some help with error handling. I have my main page: <?php include("includes/variables.php"); ?> <html> <head> <link href="includes/style.css" rel="stylesheet" type="text/css" /> <title><?php echo $sitename; ?></title> </head> <body> <center> <h1>Login Here!</h1> <form name="login_form" method="post" action="check_user.php"> <table id="login_table"> <tr> <td>Username</td> <td>:</td> <td><input name="username" type="text"></td> <td id="username_empty"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="password" type="password"></td> <td id="password_empty"></td> </tr> <tr> <td></td> <td></td> <td><input type="submit" name="submit_login" value="Log In"></td> </tr> </table> </form> </center> </body> </html> Then I have the check_user.php: <?php //include the variables include("includes/variables.php"); //define the variables from the form $username = strtolower($_POST['username']); $password = $_POST['password']; //connect to the database $connect = mysql_connect($host, $db_user, $db_pass) or die("could not connect"); //select the database $select_db = mysql_select_db($db) or die("could not select database"); //query for the database $query = "SELECT * FROM $table WHERE username='$username'"; //get the results $results = mysql_query($query); //number the rows $num_rows = mysql_num_rows($results); //put it into an array $row = mysql_fetch_array($results); //give the username and password from the database a variable $row_username = $row['username']; $row_password = $row['password']; //if the username is blank if($username == "") { echo "Please enter a username!"; } //if the password is blank else if($password == "") { echo "Please enter a password!"; } //if the username is not in the database else if($num_rows < 1) { echo "That username is not in the database!"; } //if the password is not correct else if ($password != $row_password) { echo "The password you entered does not match!"; } else { echo "You are good!"; } ?> At this point it checks that the username and password are not empty and that they are in the database and match the database. If everything is good it says "You are good!". When the user enters something incorrect it displays the error on a separate page. I want it to display the error on the same page without submitting the form. I know you can do it with ajax but am lost. Can someone please help? Link to comment https://forums.phpfreaks.com/topic/127168-solved-error-handling/ Share on other sites More sharing options...
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