[SOLVED] echo only if id[*] page is open?

[Darkwoods]

how do you write this type of code

 

echo only in id[3]  echo 'this'; if on different id do not echo 

 

for example if i am on myfile.php?id=3

[F1Fan]

Like you said, just use an if statement.

[R0bb0b]

or

<?php echo !empty($_GET['3'])?"this":""; ?>

[redarrow]

<?php

if($_GET['id']=="3"){

// code

}else{

// error code

}
?>