ve6sar Posted October 10, 2008 Share Posted October 10, 2008 I'm attempting to make a customizable report page for our companies audit database but I can't get the one query to work right. SELECT * FROM `auditrecord` WHERE `Type` = 9 OR `Type` = 10 OR `Type` = 11 OR `Type` = 12 OR `Type` = 13 AND `AuditDate` >= '2008-09-11' The query stops going through the list as soon as it gets it's first match in `Type`. So I tried moving the date to the top SELECT * FROM `auditrecord` WHERE `AuditDate` >= '2008-09-11' AND `Type` = 9 OR `Type` = 10 OR `Type` = 11 OR `Type` = 12 OR `Type` = 13 This query is built by a php script so it changes depending on what the user selects. Any Ideas? Sean Link to comment https://forums.phpfreaks.com/topic/127897-solved-query-issues/ Share on other sites More sharing options...
ngreenwood6 Posted October 10, 2008 Share Posted October 10, 2008 First of all you should really use the code tags. The next question that I have is the type coming from a post if so you can use this: <?php $type = $_POST['type']; $query = "SELECT * FROM auditrecord WHERE type = '$type'"; ?> When the user selects the type it will use that to query the database. Please let me know if that was helpful. Link to comment https://forums.phpfreaks.com/topic/127897-solved-query-issues/#findComment-662142 Share on other sites More sharing options...
Barand Posted October 10, 2008 Share Posted October 10, 2008 SELECT * FROM `auditrecord` WHERE `AuditDate` >= '2008-09-11' AND `Type` IN ( 9 ,10, 11 , 12, 13) Link to comment https://forums.phpfreaks.com/topic/127897-solved-query-issues/#findComment-662207 Share on other sites More sharing options...
ve6sar Posted October 10, 2008 Author Share Posted October 10, 2008 The `Type` comes from another query as the `auditrecord` table only contains the audit type and not the area of concern. I'm try to get it to retrieve all the audit records in a specific area. $sql = "SELECT `Type` FROM `audit_types` WHERE `AreaID` = ".$area; $result = mysql_query($sql); while ($type_raw = mysql_fetch_array($result)) { $type[] = $type_raw['Type']; } foreach ($type as $a) { if (isset ($sql_temp1)) { // Adds an OR if we all ready have something in $sql_temp $sql_temp1 = $sql_temp1." OR "; } $sql_temp1 = $sql_temp1. " `Type` = ".$a; } $sql_temp = $sql_temp1." AND ".$sql_temp; Link to comment https://forums.phpfreaks.com/topic/127897-solved-query-issues/#findComment-662212 Share on other sites More sharing options...
ve6sar Posted October 10, 2008 Author Share Posted October 10, 2008 Thanks Barand that was the ticket, works great Sean Link to comment https://forums.phpfreaks.com/topic/127897-solved-query-issues/#findComment-662237 Share on other sites More sharing options...
Barand Posted October 10, 2008 Share Posted October 10, 2008 Having seen where the types originate SELECT a.* FROM auditrecord a INNER JOIN audit_types t USING (Type) WHERE t.AreaID = '$area' Link to comment https://forums.phpfreaks.com/topic/127897-solved-query-issues/#findComment-662289 Share on other sites More sharing options...
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