table

[rashmi_k28]

<form name="myform" action="<?php $_SERVER['PHP_SELF']?>" method="post" id="id_of_the_form">

<input type="checkbox" name="check_list[]" value="bw">bw</font>
<input type="checkbox" name="check_list[]" value="cpu">Cpu
<input type="checkbox" name="check_list[]" value="rj">RJ
<input type="checkbox" name="check_list[]" value="mem">MU
<input type="checkbox" name="check_list[]" value="cnt">CA

<input name="submit_plot" value="Plot" type="submit">

$checklist=$_POST['check_list'];

<table border="1" cellspacing="3" cellpadding="5" BORDERCOLOR="#660033">
        <tbody><tr height="25" bgcolor="#DCC58F">
                <?
                 foreach($col_head as $ch){
                echo "<td>";
                echo $ch;
                echo "</td>";
              }
              echo "</tr>";

 

 

How to print the table by passing the value in ajax

 

[djbuddhi]

ur question not clear .if u tell the requirement correctly .i might help

 

[rashmi_k28]

When the check box is selected automatically the page should get refreshed using ajax and the values should be displayed within the table.

[F1Fan]

Do you know anything about AJAX? If not, you should really go through a tutorial. Otherwise you're just asking someone to right your code for you.

[alexweber15]

F1Fan is right... I'm gonna throw you a bone though

 

here's my quick and dirty (and prolly containing one or two typos) example on submitting a form using ajax

 

http://www.phpfreaks.com/forums/index.php/topic,221116.0.html