matthewc Posted October 20, 2008 Share Posted October 20, 2008 I am trying to modify a script which retrieves a websites statistics like page rank, inbound links etc. Originally the script displayed the statistics on the same page where the user inputs his/her website url to be checked. I want the script to transfer the user to another page (/results.php) so that the statistical results are displayed on a seperate page. I have tried and tried however I cannot figure out how to do it. This should be quite an easy question to php users. Please help me.. Here are the 3 scripts which are related to this problem. (there are other scripts which retrieve the statistics but they are not related with my problem so I will not include them.): ***** index.html ***** <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>PageRank Script</title> <link href="./css/main.css" rel="stylesheet" /> <script language="javascript" type="text/javascript" src="./js/main.js"></script> </head> <body> <? // Call results.php to be displayed after user clicks submit ?> <form action="./results.php" method="post" id="form"> <h1>Check Your PageRank!</h1> <label for="url" title="Enter the URL of the website you want the PageRank for">URL:</label><br /> <input type="text" name="url" id="url" value="http://" class="input" /><br /> <input type="submit" value="Get PageRank!" class="button" /><br /> <img src="img/loading.gif" id="loading" /> <div id="results"></div> </form> </body> </html> ***** results.php ***** <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> </head> <body> <?php error_reporting(E_ALL ^ E_NOTICE); // Check whether user inputted URL contains 'http' if (trim($_GET['url']) && trim($_GET['url']) != 'http://') { include './php/rank.class.php'; $url = get_magic_quotes_gpc() ? urldecode(stripslashes($_GET['url'])) : urldecode($_GET['url']); $rank = new rank($url); // Set up array containing all statistics details $s = array('$url', '$pagerank', '$alexa_rank', '$backlinks', '$msn', '$yahoo'); // Call rank.class.php and obtain values for statistics details $backlinks = ceil(($rank->backlinks['google'] + $rank->backlinks['yahoo'] + $rank->backlinks['msn'] + $rank->backlinks['altavista'] + $rank->backlinks['alltheweb']) / 5); $r = array($rank->url, $rank->pagerank, $rank->format_number($rank->alexa_rank), $rank->format_number($backlinks), $rank->format_number($rank->backlinks['msn']), $rank->format_number($rank->backlinks['yahoo'])); // Send statistics details to be displayed in template.html echo str_replace($s, $r, file_get_contents('template.html')); } else { echo 'Enter a valid URL'; } print ("PageRank for this site is: $r[1]"); ?> </body> </html> ***** template.html ***** <table> <tr> <td class="left">PageRank</td> <td class="right">$pagerank</td> </tr> <tr> <td class="left">Alexa Rank</td> <td class="right">$alexa_rank</td> </tr> <tr> <td class="left">Back Links</td> <td class="right">$backlinks</td> </tr> <tr> <td class="left">MSN Search Results</td> <td class="right">$msn</td> </tr> </table> Quote Link to comment https://forums.phpfreaks.com/topic/129157-pls-help-me-with-this-simple-newbie-question/ Share on other sites More sharing options...
thesaleboat Posted October 20, 2008 Share Posted October 20, 2008 WEll im not gonna lie but i dont really feel like looking through this entire script but it looks like you are trying to use php variables within html... so you would need to do something like this <tr> <td class="left">Back Links</td> <td class="right">$backlinks</td> </tr> change to this for all of the variables you want to show <tr> <td class="left">Back Links</td> <td class="right"><?php echo $backlinks; ?></td> </tr> Quote Link to comment https://forums.phpfreaks.com/topic/129157-pls-help-me-with-this-simple-newbie-question/#findComment-670029 Share on other sites More sharing options...
revraz Posted October 21, 2008 Share Posted October 21, 2008 You will also need to rename your .html extension to .php if you want to use PHP inside of it. Quote Link to comment https://forums.phpfreaks.com/topic/129157-pls-help-me-with-this-simple-newbie-question/#findComment-670860 Share on other sites More sharing options...
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