Help retrieving data...

[anton578]

im new to ajax.

 

function ajaxFunction(a){
var ajaxRequest;  // The variable that makes Ajax possible!

try{
	// Opera 8.0+, Firefox, Safari
	ajaxRequest = new XMLHttpRequest();
} catch (e){
	// Internet Explorer Browsers
	try{
		ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
	} catch (e) {
		try{
			ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
		} catch (e){
			// Something went wrong
			alert("Your browser broke!");
			return false;
		}
	}
}
	// Create a function that will receive data sent from the server
ajaxRequest.onreadystatechange = function(){
	if(ajaxRequest.readyState == 4){
		var ajaxDisplay = document.getElementById('ajaxDiv');
		ajaxDisplay.innerHTML = ajaxRequest.responseText; 
	}
}
var queryString = "./index.php?m=public&a=ajax&id="+a;
ajaxRequest.open("GET", queryString, true);
ajaxRequest.send(null); 
}

 

if i try that sample code. on the root directory i get no error and retrieve my desired output.but if im not in the root directory. i can get a result but my problem is i get my disired result but with additional display it also gets the header part of my main page.

 

i think this code right here is my problem.

var queryString = "./index.php?m=public&a=ajax&id="+a;

ajaxRequest.open("GET", queryString, true);

ajaxRequest.send(null);

 

i can access the ajax.php directly if i place my sample code in the root directory but when i place my code in the root directory but same folder as my page to call ajaxfunction i cant use directly the ajax.php  it will have an error "Object not found!". ill have use "./index.php?m=public&a=ajax&id="+a;"

Is there a way i can get only the output of the ajax.php.  ???

 

i really need help...

 

thanks in advance.