[SOLVED] preg_replace and vars problem?

[archonik]

A little backstory:

I store my 'items' in an array:

$a['ITEMNAME']['ITEMVALUE']

 

What I'm trying to do is build a piece of BBCode that will allow me to print the value of a provided 'item'... But trying to do so... Fails MISERABLY.

 

My code is (one of the X-ty versions I tried:)

 

$value = preg_replace("/[var](.+?)[/var]/", $a[$1]['itemvalue']', $output);

 

I tried many things... putting the $1 in {} etc. etc. but noting seems to work. Is there any way around that? The replace pattern works ok itself but it's the putting the thing inbetween and using it as a variable... complicates everything... Help, please?

[effigy]

<pre>
<?php
$a = array();
$a['test']['itemvalue'] = 123;
$output = '0[var]test[/var]456789';
echo preg_replace('%\[var\](.+?)\[/var\]%e', '$a["$1"]["itemvalue"]', $output);
?>
</pre>

[archonik]

Thank You. That worked great. How do you learn regular expressions without making your brain explode is beyond me... Thanks!

[effigy]

Carefully Look here.