mattwal Posted November 24, 2008 Share Posted November 24, 2008 Hello, I am working on a comment form for my blog and am having trouble getting the variable post_id that was passed through the URL inserted into my comments table on my database. this is the link that i use to pass the post_id variable from the index page: <a href=\"javascript:comment('comment_form.php?aid={$row['post_id']}');\" title=\"Make A Comment On This Post\">Comment</a> From there it does pass it to the comment_form.php page as comment_form.php?aid=3. So I do know it is working that far. From there I need to insert the "aid=3" or "3" being the post_id into a hidden form value to be inseted into the comments table. This is my table definitions for comments: comment_id post_id name comment date_entered This is the comment_form page script: <?php $page_title = 'Matt-Walko: Comment Page'; ?> <?php //This script adds a comment entry to the database via the $_GET['aid'] variable. //address error handling ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); if(isset ($_POST['submit'])) { //Handles the form //Connect and select require_once ("./assets/mysql_connect.php"); //Define the query $aid = $_GET["aid"]; $query = "INSERT INTO comments (comment_id, post_id, name, comment, date_entered) VALUES (0, '{$_GET['aid']}', '{$_POST['name']}','{$_POST['comment']}', NOW())"; //Execute the query if (@mysql_query ($query)) { print '<p>The blog entry has been added.</p>'; } else { print "<p>Could not add the entry because: <b>" . mysql_error() . "</b>. The query was $query.</p>"; } mysql_close(); } //end of form handler //Display the form ?> <?php $_GET['aid'] ?> <form class="form" action="comment_form.php" method="post"> Name: <input type="text" name="name" size="40" maxsize="100" /><br /> Teaser: <textarea name="comment" cols="40" rows="10"></textarea><br /> <input type="hidden" name="postid" value="<?php $_GET['aid'] ?>" /> <input type="submit" name="submit" value="Add Comment!" /> </form> When I add my comment to the database everything but the post_id is entered correctly... Heres an example: comment_id post_id name comment date_entered 1 0 Matt This is a comment 2008-11-24 02:16:20 The post_id Should be 3 instead of 0 but I didnt do something right... I cant find a decent example to work from and thought someone on here might be able to help. I really would be most appreciative. Link to comment https://forums.phpfreaks.com/topic/133994-solved-passing-variables-by-url-issue/ Share on other sites More sharing options...
Mchl Posted November 24, 2008 Share Posted November 24, 2008 try echo $_GET['aid']; to see what value it has. This: <input type="hidden" name="postid" value="<?php $_GET['aid'] ?>" /> will not work. You have to echo the value: <input type="hidden" name="postid" value="<?php echo $_GET['aid']; ?>" /> \And the form itself uses POST, and not GET, so the postid is passed to $_POST['aid'] Link to comment https://forums.phpfreaks.com/topic/133994-solved-passing-variables-by-url-issue/#findComment-697474 Share on other sites More sharing options...
mattwal Posted November 24, 2008 Author Share Posted November 24, 2008 Thank you for your quick reply... I added the suggestions you gave and saw that in my sql insertion code that i was not referring to postid name of the hidden value form also so I got it all working thank you again. Link to comment https://forums.phpfreaks.com/topic/133994-solved-passing-variables-by-url-issue/#findComment-697482 Share on other sites More sharing options...
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