[SOLVED] Quick string question

[The Bat]

Hi everyone, my PHP skills are a bit rusty, so...

 

I'm using

basename($_SERVER['PHP_SELF'])

to get (for example) blahblah_blah_stuff.php.

 

What would be the best way to extract just the word "stuff" (the word right before ".php" and right after the last underscore) from it?

 

[flyhoney]

Here is a regular expression you can use:

 

<?php
$pattern = '/([^_]+)\.[\w]+$/';
$subject = basename($_SERVER['PHP_SELF']);
preg_match($pattern, $subject, $matches);
print_r($matches);
?>

[flyhoney]

This goofy solution might work too...

 

<?php
$file = basename($_SERVER['PHP_SELF']);
$file = substr(strrpos($file, '_') + 1, strrpos($file, '.') + 1); 
?>

[flyhoney]

Nevermind that last one doesn't work. lol.

[flyhoney]

But this works!  I wouldn't use it though....

 

<?php
$file = 'blahblah_blah_stuff.php';
$file = substr($file, strrpos($file, '_') + 1, strrpos($file, '.')- strrpos($file, '_') - 1 ); 
echo $file;
?>

[flyhoney]

Here is a function that you could use, it is a little more robust.  Covers several cases:

 

<?php
function foo($string) 
{
$parts = explode('_', $string);

if (count($parts) > 0) 
{
	$end = end($parts);

	if (($pos = strrpos($end, '.')) !== false) 
	{
		return substr($end, 0, $pos);
	} 
	else 
	{
		return $end;
	}
}
return $string;
}
?>

[.josh]

<?php
$string = "blahblah_blah_stuff.php";
$postfix = $postfix[count($postfix = preg_split('/_|\./',$string))-2];
echo $postfix;
?>

[The Bat]

<?php
$string = "blahblah_blah_stuff.php";
$postfix = $postfix[count($postfix = preg_split('/_|\./',$string))-2];
echo $postfix;
?>

 

Thanks for the help everyone, I'll go with Crayon's solution.