[SOLVED] Why wont this work?

[Jpoel]

Its simple enough, but when i run the php script it returns null  ???

Anyone got any idea whats up?

 

$Month = "Aug";
$Months = array("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec");
$MonthNumber = array_search($Month,$Months);
die($MonthNumber);

 

Thanks :/

[wildteen88]

Code runs fine when you use echo and not die.

[Jpoel]

Code runs fine when you use echo and not die.

 

Cheers! Strange why that wouldnt work

I wanted the code to stop executing there, so i changed

 

die($MonthNumber);

 

to

 

echo $MonthNumber;

die();

 

And it worked fine

 

Thanks again

 

[PFMaBiSmAd]

It's because die() expects a string in order to print it. An integer cause that value to be returned to the calling program (assuming php was called by another program that expects a return value.)

If status is a string, this function prints the status just before exiting.

 

If status is an integer, that value will also be used as the exit status. Exit statuses should be in the range 0 to 254, the exit status 255 is reserved by PHP and shall not be used. The status 0 is used to terminate the program successfully.

 

Note: PHP >= 4.2.0 does NOT print the status if it is an integer.

 

This works -

 

die("$MonthNumber");