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[SOLVED] php variables

steveh62

By steveh62
in PHP Coding Help

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steveh62 Member

steveh62

Posted
Posted

I have a php variable which pushes out some html etc etc. How can I break it so I can insert a function and then re-continue pushing the rest of the html? SEE WHERE i NEED THE FUNCTION IN THE CODE.

 

and this is the function I need to insert

 

<?php
$keywords = explode(',', $keywords);
foreach($keywords as $i){
$keywords = $i;
echo '<a href="#" class="orange">'.$keywords.'</a> ';
}
?>

 

<?php
$result_final ="
  <tr> 
    <td  valign='top'><div id='mainimage'>
<a href='index.php?gid=$gid&image_max=$image_max&page=$page'><img src='site_images/back_btn.gif' border='0' title='back' alt='back'></a>
<img src='".$images_dir."/".stripslashes($filename)."' border='0' alt='$title' title='$title'><br/>
<table width='300' colspan='2'>
<tr><td class='dropdown'>Keywords: <span class='orange'> --FUNCTION INSERT HERE-- </span></td></tr>
</table><br>
<table width='300' border='0' cellspacing='0' cellpadding='5'>
 <tr> 
    <td COLSPAN='2' class='dropdown'><b>extra info</b></td>
  </tr>
  <tr> 
    <td width='100'><img src='site_images/gallery_wrap_im.gif' width='100' height='83' alt='gallery wrap' title='gallery wrap'></td>
    <td valign='top' class='dropdown'><b>Gallery wrap.</b><br>
      The canvas is wrapped around the frame fully and the image appears on the 
      sides of the frame as well as the front</td>
  </tr>
  <tr> 
    <td><img src='site_images/face_wrap_im.gif' width='100' height='83' alt='face wrap' title='face wrap'></td>
    <td valign='top' class='dropdown'><b>Face wrap.</b><br>
      The image appears on the front of the canvas only leaving white edges</td>
  </tr>
</table>
</td>
    <td  valign='top' align='left'>

<div id='mainimagetitle'>
title: $title<br/>
<div id='detaildesc'>
 $desc
 <br/><br/>
 $output
</div></div><br/></div>
</td></div>
  </tr><script language='javascript' type='text/javascript'>
CanvasFunction();
</script>
";
	}
}

// Final Output
echo <<<__HTML_END

<html>
<head>
<title></title>
</head>
<body>
<table width='100%' border='0' align='left' style='width: 100%;'>
$result_final		
</table>
</body>
</html>

__HTML_END;
?>

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steveh62 Member

steveh62

Posted
  • Author
Posted

if I tried the following it will error for some reason.

 

the error...syntax error, unexpected '.'

 

<?php
resultend ="<tr><td class='dropdown'>Keywords: <span class='orange'>".
$fetchkeywords = explode(',', $keywords);
foreach($fetchkeywords as $i){
$showkeywords = $i;
echo '<a href='#'>$showkeywords</a>';
}

."</span></td></tr>";

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Mchl Regular Member

Mchl

Posted
Posted

My... you really think PHP is magic, don't you? :P

 

$result_final ="
  <tr> 
    <td  valign='top'><div id='mainimage'>
   <a href='index.php?gid=$gid&image_max=$image_max&page=$page'><img src='site_images/back_btn.gif' border='0' title='back' alt='back'></a>
   <img src='$images_dir/".stripslashes($filename)."' border='0' alt='$title' title='$title'><br/>
   <table width='300' colspan='2'>
   <tr><td class='dropdown'>Keywords: <span class='orange'>";

$keywords = explode(',', $keywords);
foreach($keywords as $i){
  $keywords = $i;
  $result_final .= "<a href='#' class='orange'>$keywords</a>";
}

$result_final .= "</span></td></tr>
   </table><br>
   <table width='300' border='0' cellspacing='0' cellpadding='5'>
    <tr> 
    <td COLSPAN='2' class='dropdown'><b>extra info</b></td>
  </tr>
  <tr> 
    <td width='100'><img src='site_images/gallery_wrap_im.gif' width='100' height='83' alt='gallery wrap' title='gallery wrap'></td>
    <td valign='top' class='dropdown'><b>Gallery wrap.</b><br>
      The canvas is wrapped around the frame fully and the image appears on the 
      sides of the frame as well as the front</td>
  </tr>
  <tr> 
    <td><img src='site_images/face_wrap_im.gif' width='100' height='83' alt='face wrap' title='face wrap'></td>
    <td valign='top' class='dropdown'><b>Face wrap.</b><br>
      The image appears on the front of the canvas only leaving white edges</td>
  </tr>
</table>
   </td>
    <td  valign='top' align='left'>
   
   <div id='mainimagetitle'>
   title: $title<br/>
   <div id='detaildesc'>
    $desc
    <br/><br/>
    $output
   </div></div><br/></div>
   </td></div>
  </tr><script language='javascript' type='text/javascript'>
CanvasFunction();
</script>
";

 

Seriously. You should go and find some PHP book (and read it :P )

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steveh62 Member

steveh62

Posted
  • Author
Posted

quite frankly yes...its a progam language with structure and logic...so those that can remember thousands of syntax issues and amend them... then great. But until I master all of the 'geekery' I feel I have to ask and test...and yes I have books.

 

Thanks for the solution anyhew :)

 

Basically I thought you could only break out and in to code using .

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Mchl Regular Member

Mchl

Posted
Posted

It might seem, that there 'thousands of syntax issues' in PHP, but in fact I doubt there is more than 100 strict rules, you have to follow to avoid syntax errors. It really is not that difficult.

 

BTW: . (called concatenation operator) is used to join strings together, so "abc"."def" becomes "abcdef".

 

Read more in manual

 

 

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