Vizionz Posted January 2, 2009 Share Posted January 2, 2009 CREATE TABLE `Artists` ( `ID` int(6) unsigned NOT NULL auto_increment COMMENT 'The unique ID', `Artist` varchar(200) default NULL COMMENT 'The Artist', `ArtistID` varchar(200) default NULL COMMENT 'The Artist Id', `Formed` varchar(200) default NULL COMMENT 'Band Formed', `Picture` varchar(200) default NULL COMMENT 'The band Artist Picture', `Members` text COMMENT 'The Band Members', `Genres` int(4) default '0' COMMENT 'Genre of the artist', `Bio` text COMMENT 'The Biography', `Website` varchar(200) default NULL COMMENT 'The Artists Website', `Myspace` varchar(200) default NULL COMMENT 'The Artists Myspace', PRIMARY KEY (`ID`) ) ENGINE=MyISAM AUTO_INCREMENT=4 DEFAULT CHARSET=latin1 AUTO_INCREMENT=4 ; CREATE TABLE `Genres` ( `ID` int(4) unsigned NOT NULL auto_increment COMMENT 'The unique ID of the section', `name` varchar(20) default NULL COMMENT 'The Genre name', `parentid` int(4) default '0' COMMENT 'The ID of the parent section', PRIMARY KEY (`ID`) ) ENGINE=MyISAM AUTO_INCREMENT=16 DEFAULT CHARSET=latin1 AUTO_INCREMENT=16 ; $result = $connector->query('SELECT Artist,Genres,Bio FROM Artists WHERE ID = '.$HTTP_GET_VARS['id']); now as is the last code. that will get me the artist the bio and the genre from the artist table. but i need to take that genre from artist and then take that result and replace it with the relevant row in the genre table. as of now it just gives me the id from the Artists (genres row) i need the name from the genres table so i can echo but dont know how to query that <?php echo $row['Genres'];?> and if you find anything wrong with the way the tables are in mysql please help i am trying to learn to write code and i am novice Quote Link to comment https://forums.phpfreaks.com/topic/139146-need-query-help/ Share on other sites More sharing options...
gwydionwaters Posted January 2, 2009 Share Posted January 2, 2009 $result = $connector->query('SELECT Artist,Genres,Bio FROM Artists WHERE ID = '.$HTTP_GET_VARS['id']); to get the genre name instead of the id <?php $result = $connector->query('SELECT Artists.Artist,Artists.Bio,Genres.Name FROM Artists INNER JOIN Genres ON Artists.Genres=Genres.Id WHERE ID = '.$HTTP_GET_VARS['id']); you can also do it like <?php $result = $connector->query('SELECT Artist,Bio,Name FROM Artists INNER JOIN Genres ON Artists.Genres=Genres.Id WHERE ID = '.$HTTP_GET_VARS['id']); i just like to use the table.field format for ease of reading. oh and because of the name used in the genres table you will have to echo Name instead of Genre Quote Link to comment https://forums.phpfreaks.com/topic/139146-need-query-help/#findComment-727825 Share on other sites More sharing options...
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