dezkit Posted January 6, 2009 Share Posted January 6, 2009 I bet your going WTF by reading the topic subject, but... I have this code example.html <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.min.js"></script> <script type="text/javascript"> function checkForData ( ) { jQuery.get('data.php',false,function(data){ if(data.length){ //Do something with the data document.getElementById('my_response').innerHTML += "Found data: " + data + "\n"; }else{ //This is just so we can watch it work document.getElementById('my_response').innerHTML += "No data found\n"; } }); } //Start the timer when the page is done loading: $(function(){ //Run it immediately checkForData(); //Start timer setInterval('checkForData()',5000); //I used 5 seconds for testing }); </script> <pre id="my_response"></pre> data.php <?php $rand = rand(); echo $rand; ?> How do I do so that the ajax just refreshes the current rand() instead of adding on top of each other? Link to comment https://forums.phpfreaks.com/topic/139666-solved-refresh-the-current-line-not-add-on-anything-else-ajax-php/ Share on other sites More sharing options...
jazz Posted January 6, 2009 Share Posted January 6, 2009 document.getElementById('my_response').innerHTML += "Found data: " + data + "\n"; document.getElementById('my_response').innerHTML += "No data found\n"; Replace += with = . Link to comment https://forums.phpfreaks.com/topic/139666-solved-refresh-the-current-line-not-add-on-anything-else-ajax-php/#findComment-730837 Share on other sites More sharing options...
dezkit Posted January 6, 2009 Author Share Posted January 6, 2009 It works! Thanks! Link to comment https://forums.phpfreaks.com/topic/139666-solved-refresh-the-current-line-not-add-on-anything-else-ajax-php/#findComment-731000 Share on other sites More sharing options...
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