lukelee Posted January 6, 2009 Share Posted January 6, 2009 Now I can save both thumbnail and original image into folder, but i can only save the original image name into database. I think the problem is thumbnail code is within a class, and 'insert into' is outside of the class, see the red line. can anyone help me with that? <?php require_once('db.php'); $address = $_POST[house_address]; class resizeimage { var $type; var $width; var $height; var $resize_width; var $resize_height; var $cut; var $srcimg; var $dstimg; var $im; function resizeimage($img, $wid, $hei,$c) { $this->srcimg = $img; $this->resize_width = $wid; $this->resize_height = $hei; $this->cut = $c; $this->type = substr(strrchr($this->srcimg,"."),1); $this->initi_img(); $this -> dst_img(); $this->width = imagesx($this->im); $this->height = imagesy($this->im); $this->newimg(); ImageDestroy ($this->im); } function newimg() { $resize_ratio = ($this->resize_width)/($this->resize_height); $ratio = ($this->width)/($this->height); if(($this->cut)=="1") { if($ratio>=$resize_ratio) { $newimg = imagecreatetruecolor($this->resize_width,$this->resize_height); imagecopyresampled($newimg, $this->im, 0, 0, 0, 0, $this->resize_width,$this->resize_height, (($this->height)*$resize_ratio), $this->height); ImageJpeg ($newimg,$this->dstimg); echo " "; } if($ratio<$resize_ratio) { $newimg = imagecreatetruecolor($this->resize_width,$this->resize_height); imagecopyresampled($newimg, $this->im, 0, 0, 0, 0, $this->resize_width, $this->resize_height, $this->width, (($this->width)/$resize_ratio)); ImageJpeg ($newimg,$this->dstimg); echo " !"; } } else { if($ratio>=$resize_ratio) { $newimg = imagecreatetruecolor($this->resize_width,($this->resize_width)/$ratio); imagecopyresampled($newimg, $this->im, 0, 0, 0, 0, $this->resize_width, ($this->resize_width)/$ratio, $this->width, $this->height); ImageJpeg ($newimg,$this->dstimg); echo " "; } if($ratio<$resize_ratio) { $newimg = imagecreatetruecolor(($this->resize_height)*$ratio,$this->resize_height); imagecopyresampled($newimg, $this->im, 0, 0, 0, 0, ($this->resize_height)*$ratio, $this->resize_height, $this->width, $this->height); ImageJpeg ($newimg,$this->dstimg); echo " "; } } } function initi_img() { if($this->type=="jpg") { $this->im = imagecreatefromjpeg($this->srcimg); } if($this->type=="gif") { $this->im = imagecreatefromgif($this->srcimg); } if($this->type=="png") { $this->im = imagecreatefrompng($this->srcimg); } } function dst_img() { $full_length = strlen($this->srcimg); $type_length = strlen($this->type); $name_length = $full_length-$type_length; $name = substr($this->srcimg,0,$name_length-1); $this->dstimg = $name."_small.".$this->type; $new_small = basename($this->dstimg); echo "Image has been edited, will go back to previous page in 3 sencond"; } } $tempimgname = strtolower($_FILES["image1"][name]); $tempimgname = mb_convert_encoding( $tempimgname, "gb2312", "utf-8"); $tmpfiletype = substr(strrchr($tempimgname,"."),1); if($tmpfiletype=="jpg" || $tmpfiletype=="gif" || $tmpfiletype=="png") { if(copy($_FILES["image1"]["tmp_name"],strtolower("upload/".date("Y-m-d-h-m-s",time()).$tempimgname))) { $image1 = basename(strtolower("upload/".date("Y-m-d-h-m-s",time()).$tempimgname)); $class = new resizeimage("upload/".date("Y-m-d-h-m-s",time()).$tempimgname, 260, 260, 1); $query = mysql_query("insert into house (address,thumb,imagedata1,imagedata) values ('$address','1','$new_small','$image1')"); } else { echo "Upload failed"."<br>"; } } else { echo "image only allows jpg,gif,png"; } ?> Link to comment https://forums.phpfreaks.com/topic/139748-how-to-save-my-thumbnail-image-name-into-database/ Share on other sites More sharing options...
lukelee Posted January 6, 2009 Author Share Posted January 6, 2009 is this a difficult task? someone help plz. Link to comment https://forums.phpfreaks.com/topic/139748-how-to-save-my-thumbnail-image-name-into-database/#findComment-731214 Share on other sites More sharing options...
cytech Posted January 6, 2009 Share Posted January 6, 2009 Yes, since the $new_small variable is local inside of the class you can not access it as you are. However; looking at the code the variable "dstimg" is holding the new images name. So update your new_image variable to this: $query = mysql_query("insert into house (address,thumb,imagedata1,imagedata) values ('$address','1','{$class->dstimg}','$image1')"); See if that does the trick. Link to comment https://forums.phpfreaks.com/topic/139748-how-to-save-my-thumbnail-image-name-into-database/#findComment-731217 Share on other sites More sharing options...
lukelee Posted January 7, 2009 Author Share Posted January 7, 2009 Yes, since the $new_small variable is local inside of the class you can not access it as you are. However; looking at the code the variable "dstimg" is holding the new images name. So update your new_image variable to this: $query = mysql_query("insert into house (address,thumb,imagedata1,imagedata) values ('$address','1','{$class->dstimg}','$image1')"); See if that does the trick. thanks for help man! Link to comment https://forums.phpfreaks.com/topic/139748-how-to-save-my-thumbnail-image-name-into-database/#findComment-731271 Share on other sites More sharing options...
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