richrock Posted January 7, 2009 Share Posted January 7, 2009 Hi, I'm having a little trouble :-\ SOLVED IT - I'm such a muppet - all I had to do was DISTINCT on the first item in the query (jos_comprofiler.user_id) and it works. Sorry! I've created a system to allow people to register interest in items for sale prior to 'release'. They do this over the phone, and an administrator basically ticks off the items and it gets stored into a database: id / item_id / client_id I did this so that more than one person can be interested is the same item. However, when creating a dropdown with names based on client_id, I get multiple names. As I'm using a join across the tables, I can't figure how I'm going to allow it to be distinct names, or is there another way? Here's the db query: $view_telebidders = "SELECT jos_comprofiler.user_id, firstname, lastname "; $view_telebidders .= "FROM jos_comprofiler "; $view_telebidders .= "LEFT JOIN jos_bid_telebids "; $view_telebidders .= "ON bidder_id "; $view_telebidders .= "WHERE jos_bid_telebids.bidder_id = jos_comprofiler.user_id "; $view_telebidders .= "ORDER BY lastname ASC"; $res_telebidders = mysql_query($view_telebidders) or die(mysql_errno() . mysql_error()); // GENERATE $row_select_telebidders = mysql_fetch_assoc($res_telebidders); $totalRows_select_telebidders = mysql_num_rows($res_telebidders); And here's the dropdown: <td><select name="teleselect" onchange="this.form.submit()"> <option value='none'>-- Select Telephone Bidder --</option> <?php do { if ($useridassign==$row_select_telebidders['user_id']) { echo "<option value ='".$row_select_telebidders['user_id']."' selected>".$row_select_telebidders['firstname']." ".$row_select_telebidders['lastname']."</option>"; } else { echo "<option value ='".$row_select_telebidders['user_id']."'>".$row_select_telebidders['firstname']." ".$row_select_telebidders['lastname']."</option>"; } } while ($row_select_telebidders = mysql_fetch_assoc($res_telebidders)); $rows = mysql_num_rows($res_telebidders); if($rows > 0) { mysql_data_seek($res_telebidders, 0); $row_select_telebidders = mysql_fetch_assoc($res_telebidders); } ?> </select></td> Last, but not least, source code of the output, so you can see the duplicates: <td><select name="teleselect" onchange="this.form.submit()"> <option value='none'>-- Select Telephone Bidder --</option> <option value ='7797'>Robert Bringham</option> <option value ='7814'>Johan Hansson</option> <option value ='7814'>Johan Hansson</option> <option value ='7820'>Stephen Smith</option> <option value ='7820'>Stephen Smith</option> </select></td> It's odd that Robert Bringham only comes up once. What's gone wrong? ??? Quote Link to comment https://forums.phpfreaks.com/topic/139863-solved-distinct-people-in-a-dropdown-select/ Share on other sites More sharing options...
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