Gubbins Posted January 10, 2009 Share Posted January 10, 2009 I currently have this in some of my scripts and it works fine:- print ("<link rel=\"stylesheet\" type=\"text/css\" href=\"connections/style.css\" />"); But i want to covert this:- <link href="<? echo $style_g; ?>" rel="stylesheet" type="text/css"> Into the same format, can anyone help please? Quote Link to comment Share on other sites More sharing options...
killah Posted January 10, 2009 Share Posted January 10, 2009 Isn't print(''); already part of the php syntax? And if so why would you want to take it out of the print syntax. I would use this: echo '<link rel="stylesheet" type="text/css" href="' . $style_g . '">'; Quote Link to comment Share on other sites More sharing options...
Gubbins Posted January 10, 2009 Author Share Posted January 10, 2009 killah You are a star, it worked a treat! Thank you very much! I wish i had you coding for me! Quote Link to comment Share on other sites More sharing options...
killah Posted January 11, 2009 Share Posted January 11, 2009 Glad to help. Quote Link to comment Share on other sites More sharing options...
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