darkfreaks Posted January 17, 2009 Share Posted January 17, 2009 how do i do this correctly? i try to call it in the css image background url function and it doesnt want to pass? background-image: url(http://www.chickapets.com/images/user_images/opg_1/dd/<?=$top[top]?>.png); Quote Link to comment https://forums.phpfreaks.com/topic/141184-solved-passing-php-through-css/ Share on other sites More sharing options...
aximbigfan Posted January 17, 2009 Share Posted January 17, 2009 You will have to put it in a .php file, otherwise it may not be parsed. Otherwise, I think that's it.... Chris Quote Link to comment https://forums.phpfreaks.com/topic/141184-solved-passing-php-through-css/#findComment-738948 Share on other sites More sharing options...
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