[SOLVED] Picture Specific Size

[Solar]

Oh my, I feel so newbish! But this is not working out. This is for the user's picture on their profile page and I want a specific height and width, I will use 150x150 to deminstrate.

 

This code does not work..

 

<?php
echo "<img src=http://72.38.175.121/photo/".$req_user_info['username']." width="150" height="150">";
?>

 

I have to echo it to make; ".$req_user_info['username']." to work. Then the width and height becomes the problem.

 

Error:

Parse error: syntax error, unexpected T_LNUMBER, expecting ',' or ';' in C:\xampp\htdocs\userinfo.php on line 81

[nuttycoder]

use backslashes on all double quotes that are inside double qoutes

 

<?php
echo "<img src=\"http://72.38.175.121/photo/".$req_user_info['username']." width=\"150\" height=\"150\" >";
?>

 

you can put brackets in double quotes as well just put them inside {}

 

<?php
echo "<img src=\"http://72.38.175.121/photo/{$req_user_info['username']}\" width=\"150\" height=\"150\" >";
?>

[Solar]

Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in C:\xampp\htdocs\userinfo.php on line 82

 

I think I allready tried that. Seems like there are to many slashes.

 

 

Backslashes shows my picture as..

 

"http://72.38.175.121/photo/Steven%20width="

 

Nothing else

[nuttycoder]

yeah I noticed mistakes in my code I've updated it

[Solar]

Both show as "http://72.38.175.121/photo/Steven%20width=""

[nuttycoder]

I've just ran this code

 

$name = 'dave';
echo "<img src=\"http://72.38.175.121/photo/{$name}\" width=\"150\" height=\"150\" >";

 

Outputs

<img src="http://72.38.175.121/photo/dave" width="150" height="150" >

 

won't show in the page as there is no image there.

[Solar]

Thank you for your help so far and I see where you are getting with this. But what you just wrote for the second time would be the exactly the same as your first code. I can't substitute $username = $username because that wont work, I can't substitute $username = ".$req_user_info['username']."  because I recieve the same error as the first time.

 

I think this is a tricky one

[nuttycoder]

What do you get if you use:

 

<?php
echo "<img src=\"http://72.38.175.121/photo/".$req_user_info['username']." width=\"150\" height=\"150\" >";
?>

[Solar]

What do you get if you use:

 

<?php
echo "<img src=\"http://72.38.175.121/photo/".$req_user_info['username']." width=\"150\" height=\"150\" >";
?>

 

Same error posted above. I added;

<?php
echo "<img src=\"http://72.38.175.121/photo/".$req_user_info['username']."\ width=\"150\" height=\"150\" >";
?>

 

Gives me;

"http://72.38.175.121/photo/Steven\%20width="

 

Some reason its thinking that the width and height is part of the URL and stops at the first quotation mark. I'll play with it untilll we figure it out

[nuttycoder]

if the image source is http://72.38.175.121/photo/Steven then you won't see anything on screen only in your source code.

 

It is strange how your getting no space between the username and width though.

[Solar]

if the image source is http://72.38.175.121/photo/Steven then you won't see anything on screen only in your source code.

 

It is strange how your getting no space between the username and width though.

 

Haha, I know thats why I thought I'd ask.

 

I'm working this on a different page;

http://72.38.175.121/userinfo2.php?user=Steven

 

It will be a pain if people upload there big pictures

[nuttycoder]

you can restrict the actual file size or better yet resize their image on upload.

[Solar]

I got it man..

 

echo "<img src=\"http://72.38.175.121/photo/".$req_user_info['username']."\"\width=\"150\" height=\"150\" >";

 

I added an extra "\

 

That way there the width and the height are not acting like links.

 

Thanks for all your help!

[nuttycoder]

your welcome glad you got it working.