aznkidzx Posted February 2, 2009 Share Posted February 2, 2009 Warning: copy(images/1233614813.jpg) [function.copy]: failed to open stream: Permission denied in upload.php on line 58 Why does this happen? I am using this script for uploading images using file extensions jpg jpeg and png. How do I fix this problem? -------------------------------------------- I followed a tutorial for the script.. The demo worked fine.. Quote Link to comment Share on other sites More sharing options...
Michdd Posted February 2, 2009 Share Posted February 2, 2009 You need to CHMOD the directory. Quote Link to comment Share on other sites More sharing options...
flyhoney Posted February 2, 2009 Share Posted February 2, 2009 you need to change the file permissions for the 'images' directory. You can do this using your FTP client. Right click the folder in your FTP client and there should be a permissions options (it might be called 'chmod'). Make sure this folder is 'writable' by 'owner' and 'group'. Quote Link to comment Share on other sites More sharing options...
aznkidzx Posted February 2, 2009 Author Share Posted February 2, 2009 Let me try.. I'll post results.. -------------------- Should I set all permissions? Like read write and execute for owner, group, and everyone? ------------------- Also what should the chmod value be? Quote Link to comment Share on other sites More sharing options...
aznkidzx Posted February 2, 2009 Author Share Posted February 2, 2009 So sorry for double posting.. Modify button is hiding!! Also thanks for help! It works now! ;] But how do I make it so, when it says "Successful" it shows the link to the image and the image itself? -------------------- Would $_POST['image'] work? Quote Link to comment Share on other sites More sharing options...
Michdd Posted February 2, 2009 Share Posted February 2, 2009 So sorry for double posting.. Modify button is hiding!! Also thanks for help! It works now! ;] But how do I make it so, when it says "Successful" it shows the link to the image and the image itself? -------------------- Would $_POST['image'] work? I would need to see the upload script to tell you how to format the link to the uploaded image. Quote Link to comment Share on other sites More sharing options...
aznkidzx Posted February 2, 2009 Author Share Posted February 2, 2009 <?php //define a maxim size for the uploaded images in Kb define ("MAX_SIZE","2048"); //This function reads the extension of the file. It is used to determine if the file is an image by checking the extension. function getExtension($str) { $i = strrpos($str,"."); if (!$i) { return ""; } $l = strlen($str) - $i; $ext = substr($str,$i+1,$l); return $ext; } //This variable is used as a flag. The value is initialized with 0 (meaning no error found) //and it will be changed to 1 if an errro occures. //If the error occures the file will not be uploaded. $errors=0; //checks if the form has been submitted if(isset($_POST['Submit'])) { //reads the name of the file the user submitted for uploading $image=$_FILES['image']['name']; //if it is not empty if ($image) { //get the original name of the file from the clients machine $filename = stripslashes($_FILES['image']['name']); //get the extension of the file in a lower case format $extension = getExtension($filename); $extension = strtolower($extension); //if it is not a known extension, we will suppose it is an error and will not upload the file, //otherwise we will do more tests if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif")) { //print error message echo '<h1>Unknown file extension! We only upload .gif .jpg .jpeg and .png!</h1>'; $errors=1; } else { //get the size of the image in bytes //$_FILES['image']['tmp_name'] is the temporary filename of the file //in which the uploaded file was stored on the server $size=filesize($_FILES['image']['tmp_name']); //compare the size with the maxim size we defined and print error if bigger if ($size > MAX_SIZE*2048) { echo '<h1>You have exceeded the size limit!</h1>'; $errors=1; } //we will give an unique name, for example the time in unix time format $image_name=time().'.'.$extension; //the new name will be containing the full path where will be stored (images folder) $newname="images/".$image_name; //we verify if the image has been uploaded, and print error instead $copied = copy($_FILES['image']['tmp_name'], $newname); if (!$copied) { echo '<h1>Copy unsuccessfull!</h1>'; $errors=1; }}}} //If no errors registred, print the success message if(isset($_POST['Submit']) && !$errors) { echo "<h1>File Uploaded Successfully!</h1>"; } ?> <!--next comes the form, you must set the enctype to "multipart/frm-data" and use an input type "file" --> <form name="newad" method="post" enctype="multipart/form-data" action=""> <table> <tr><td><input type="file" name="image"></td></tr> <tr><td><input name="Submit" type="submit" value="Upload image"></td></tr> </table> </form> Demo : http://test.colorev.co.cc/upload.php Quote Link to comment Share on other sites More sharing options...
Michdd Posted February 2, 2009 Share Posted February 2, 2009 <?php //define a maxim size for the uploaded images in Kb define ("MAX_SIZE","2048"); //This function reads the extension of the file. It is used to determine if the file is an image by checking the extension. function getExtension($str) { $i = strrpos($str,"."); if (!$i) { return ""; } $l = strlen($str) - $i; $ext = substr($str,$i+1,$l); return $ext; } //This variable is used as a flag. The value is initialized with 0 (meaning no error found) //and it will be changed to 1 if an errro occures. //If the error occures the file will not be uploaded. $errors=0; //checks if the form has been submitted if(isset($_POST['Submit'])) { //reads the name of the file the user submitted for uploading $image=$_FILES['image']['name']; //if it is not empty if ($image) { //get the original name of the file from the clients machine $filename = stripslashes($_FILES['image']['name']); //get the extension of the file in a lower case format $extension = getExtension($filename); $extension = strtolower($extension); //if it is not a known extension, we will suppose it is an error and will not upload the file, //otherwise we will do more tests if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif")) { //print error message echo '<h1>Unknown file extension! We only upload .gif .jpg .jpeg and .png!</h1>'; $errors=1; } else { //get the size of the image in bytes //$_FILES['image']['tmp_name'] is the temporary filename of the file //in which the uploaded file was stored on the server $size=filesize($_FILES['image']['tmp_name']); //compare the size with the maxim size we defined and print error if bigger if ($size > MAX_SIZE*2048) { echo '<h1>You have exceeded the size limit!</h1>'; $errors=1; } //we will give an unique name, for example the time in unix time format $image_name=time().'.'.$extension; //the new name will be containing the full path where will be stored (images folder) $newname="images/".$image_name; //we verify if the image has been uploaded, and print error instead $copied = copy($_FILES['image']['tmp_name'], $newname); if (!$copied) { echo '<h1>Copy unsuccessfull!</h1>'; $errors=1; }}}} //If no errors registred, print the success message if(isset($_POST['Submit']) && !$errors) { echo "<h1>File Uploaded Successfully!</h1>"; echo "You can find your file <a href='" . $newname . "'>here</a>"; } ?> <!--next comes the form, you must set the enctype to "multipart/frm-data" and use an input type "file" --> <form name="newad" method="post" enctype="multipart/form-data" action=""> <table> <tr><td><input type="file" name="image"></td></tr> <tr><td><input name="Submit" type="submit" value="Upload image"></td></tr> </table> </form> Quote Link to comment Share on other sites More sharing options...
aznkidzx Posted February 2, 2009 Author Share Posted February 2, 2009 I am going to try it It works fine --------------------------------- Wait now, how do I make it so people CAN'T view the index of /images ? Quote Link to comment Share on other sites More sharing options...
Michdd Posted February 3, 2009 Share Posted February 3, 2009 A simple solution would be just to upload a index.php file inside of images/ Quote Link to comment Share on other sites More sharing options...
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