[SOLVED] If, Then... testing multiple settings of one variable

[Errant_Shadow]

Hi, I'm just curious if there is a shorter way to test one variable for multiple settings.

 

Here's the scenario:

 

// basically, I'm testing a variable to make sure it is set to an existing page, and if not, set the page to default
if($_GET['page'] != "page1" || $_GET['page'] != "page2" || $_GET['page'] != "page3" || $_GET['page'] != "page4"){
$page = "default";
} // end if($_GET['page'])

 

Is there any way I can write this so that I only enter "$_GET['page']" once, and then check it against multiple possible settings as seen above, or am I stuck writing out each statement in between each "OR"?

[Snart]

switch($_GET['page'])
{
  case "page1": case "page2":
    //Do something
    break;
  case "page3": 
    //Do something else
    break;
  default:
    //in all other cases
    break;
}

 

EDIT: spelling mistake

[Errant_Shadow]

I thought about using a switch() statement, but I don't need different things to happen for each case.

I want to make sure someone doesn't enter an invalid page variable into the url and break my code, so I need to check the page variable present against all possible pages that my script can load

 

Like, if my page can load "game" "about" and "terms" I don't want someone entering "?page=fubar" and messing it all up. if they do, I need my script to reset page to default

[PFMaBiSmAd]

Create an array with the list of values and use in_array to determine if the GET variable matches one of the values.

[Errant_Shadow]

I see, I see...

 

so... something like this?

// set available pages in $pageArray
$pageArray = array("page1", "page2", "page3", "page4");

// test posted data against $pageArray
// if invalid, reset $page to "default"
if(!in_array($_GET['page'], $pagesArray){
$page = "default";
} // end if(!in_array($_GET['page'], $pagesArray)