lsousa Posted February 5, 2009 Share Posted February 5, 2009 Yes, I know you shouldn't use regexp to parse html but this example could be applied to other things. But anyway, I have this problem: <? $input = '<html><a href="whatever">nome1</a><a href="whatever&prodID=isso">nome2</a></html>'; $ret = preg_match_all('|href="(.*?prodID=.*?)</a>|',$input,$matches); var_export($matches); ?> I want it to return only the second link, because that's the one that has prodID as an argument, but even with non-greedy search this is the result: array ( 0 => array ( 0 => 'href="whatever">nome1</a><a href="whatever&prodID=isso">nome2</a>', ), 1 => array ( 0 => 'whatever">nome1</a><a href="whatever&prodID=isso">nome2', ), ) Shoudln't array[1][0] contain only the second link? How can I do the regexp that only returns the URL of the second link: 'whatever&prodID=isso">nome2' ? Thanks Quote Link to comment Share on other sites More sharing options...
effigy Posted February 5, 2009 Share Posted February 5, 2009 Your first .*? will capture anything up to prodID, even it has to go beyond another double quote or into another tag. Try |href="([^"]+prodID=[^"]+)"[^>]*>(.*?)</a>|. Quote Link to comment Share on other sites More sharing options...
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