Merge two expressions with different mods

[Lumio]

Hello!

I got two expressions:

/(\{\$[\w\d\[\]]+\})/

ans

/(\<\<.+?\>\>/s

 

How can I merge these two expressions?

[.josh]

we can't possibly tell you that without you posting example data and what you are wanting to be matched.

[Lumio]

Okay.

 

In the first case I face the following data:

a little string with {$var} in it

the second case:

a little string with <<foo

bar >> in it

 

The first expression should just match in one line, the second in multiples.

[nrg_alpha]

Perhaps one suggestion could be?

 

$str = 'a little string with {$var} in it.
a little string with <<foo

bar >> in it';

preg_match_all('#((?:{|<<)[^}>]+(?:}|>>))#s', $str, $matches);
$matches[1] = str_replace("\r\n", '', $matches[1]); // clear out any newlines and such...
echo '<pre>'.print_r($matches[1], true);

 

Due to < and >, you'll have to view source to see the full results from the array.

 

Output:

 

<pre>Array
(
    [0] => {$var}
    [1] => <<foobar >>
)

[Lumio]

Thank you

I made it a little bit different now:

/\({\$[\w\d\[\]^\n]+\})|(\<\<.+?\>\>)/

[nrg_alpha]

First, sorry for the s modifier in my version... realized afterwards that since I'm not using a dot match all, it's not needed.. my bad. (and I forgot about adding the dollar sign in my opening alternation...):

#((?:{\$|<<)[^}>]+(?:}|>>))#

This code also assumes that if something starts with {$, it will finish with } to match {$something}.

 

Thank you

I made it a little bit different now:

/\({\$[\w\d\[\]^\n]+\})|(\<\<.+?\>\>)/

 

I don't think this will work..after your opening delimiter, you escape the first bracket \(, which means you are looking for a literal bracket in your string.. then your character class is not correct.. what this is saying is, look for any word character, or digit, or [ or ] or ^ or newline one or more times, then a \} (which you don't need to escape).

[nrg_alpha]

Another possible version:

 

preg_match_all('#((?:{\$[^}]+}|<<[^>]+>>))#', $str, $matches);