Jump to content

[SOLVED] PHP MySQL Search - Query to search selected columns from drop down menus

karl_009

By karl_009
in MySQL Help

 Share

Recommended Posts

karl_009 Member

karl_009

Posted
Posted

Hi,

 

I found some code on the internet and I have been trying to change it to work a little differently.

 

I have added a second drop down menu to the code and added parts to the SQL query but it always returns the same error;

 

Notice: Undefined variable: dropdown1 in C:\wamp\cmstesting\test1.php on line 87

 

Notice: Undefined variable: search1 in C:\wamp\cmstesting\test1.php on line 87

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'like ''' at line 1

 

 

Here is the code:

 

<html>
<head>
<basefont face="Arial">
</head>
<body>

<?php
error_reporting(E_ALL); 
if (!isset($_POST['Submit'])) {
// form not submitted
?>

<form action="<?=$_SERVER['PHP_SELF']?>" method="post">
search  
  <input type="text" name="search">
   <select size="1" name="dropdown">
    <option value="" selected>search By...</option>
    <option value="first">First Name</option>
    <option value="last">Last Name</option>
    <option value="company">Company</option>
    <option value="address">Street Name</option>
    <option value="town">Town</option>
    <option value="city">City</option>
    <option value="postcode">Postcode</option>
    <option value="mobile">Mobile Number</option>
    <option value="phone">Phone Number</option>
    <option value="email">Email Address</option>
    <option value="website">Web Address</option>
  </select>
  <br>

search1 
<input type="text" name="search1">
<select size="1" name="dropdown1">
  <option value="" selected>search By...</option>
  <option value="first">First Name</option>
  <option value="last">Last Name</option>
  <option value="company">Company</option>
  <option value="address">Street Name</option>
  <option value="town">Town</option>
  <option value="city">City</option>
  <option value="postcode">Postcode</option>
  <option value="mobile">Mobile Number</option>
  <option value="phone">Phone Number</option>
  <option value="email">Email Address</option>
  <option value="website">Web Address</option>
</select>
<br>
<input type="Submit" value="Submit" name="Submit"> 
</form>





<?php
}

else {

// Server Variables
$host = "localhost";
$user = "root";
$pass = "…….";
$db = "test";

$search = empty($_POST['search'])? die ("ERROR: Enter search Criteria") : mysql_escape_string($_POST['search']);
$dropdown = empty($_POST['dropdown'])? die ("ERROR: Select from dropdown") : mysql_escape_string($_POST['dropdown']);


// Open Connection

$connect = mysql_connect($host, $user, $pass) or die ("Unable to connect to host");

//Select Database

mysql_select_db($db) or die ("Unable to connect to database");

//Create query

$query = "SELECT * FROM contacts WHERE $dropdown like'$search' AND $dropdown1 like '$search1'" or die (mysql_error());


$result = mysql_query($query) or die (mysql_error());

$num=mysql_numrows($result);

mysql_close($connect);

echo "<b><center>Database Output</center></b><br><br>";

$i=0;
while ($i < $num) {

$first=mysql_result($result,$i,"first");
$last=mysql_result($result,$i,"last");
$company=mysql_result($result,$i,"company");
$address=mysql_result($result,$i,"address");
$town=mysql_result($result,$i,"town");
$city=mysql_result($result,$i,"city");
$postcode=mysql_result($result,$i,"postcode");
$mobile=mysql_result($result,$i,"mobile");
$phone=mysql_result($result,$i,"phone");
$email=mysql_result($result,$i,"email");
$website=mysql_result($result,$i,"website");

echo "<b>$first $last</b><br>Company: $company<br><br>Street Name: $address<br>Town: $town<br>City: $city<br>Postcode: $postcode<br>Mobile: $mobile<br>Phone: $phone<br>Email: $email<br>Website: $website<br><hr><br>";

$i++;

}
}
?>
</body>
</html>

 

I have also tried this;

$query = "SELECT * FROM contacts WHERE $dropdown='$search' AND $dropdown1='$search1'" or die (mysql_error());

 

Many thanks for any help…

Karl

 

Link to comment
Share on other sites
karl_009 Member

karl_009

Posted
  • Author
Posted

Hey,

 

I found the solution;

 

<html>
<head>
<basefont face="Arial">
</head>
<body>

<?php
error_reporting(E_ALL); 
if (!isset($_POST['Submit'])) {
// form not submitted
?>

<form action="<?=$_SERVER['PHP_SELF']?>" method="post">
search  
  <input type="text" name="search">
   <select size="1" name="dropdown">
    <option value="" selected>search By...</option>
    <option value="first">First Name</option>
    <option value="last">Last Name</option>
    <option value="company">Company</option>
    <option value="address">Street Name</option>
    <option value="town">Town</option>
    <option value="city">City</option>
    <option value="postcode">Postcode</option>
    <option value="mobile">Mobile Number</option>
    <option value="phone">Phone Number</option>
    <option value="email">Email Address</option>
    <option value="website">Web Address</option>
  </select>
  <br>

search1 
<input type="text" name="search1">
<select size="1" name="dropdown1">
  <option value="" selected>search By...</option>
  <option value="first">First Name</option>
  <option value="last">Last Name</option>
  <option value="company">Company</option>
  <option value="address">Street Name</option>
  <option value="town">Town</option>
  <option value="city">City</option>
  <option value="postcode">Postcode</option>
  <option value="mobile">Mobile Number</option>
  <option value="phone">Phone Number</option>
  <option value="email">Email Address</option>
  <option value="website">Web Address</option>
</select>
<br>
<input type="Submit" value="Submit" name="Submit"> 
</form>





<?php
}

else {

// Server Variables
$host = "localhost";
$user = "root";
$pass = "kayla";
$db = "test";

$search = empty($_POST['search'])? die ("ERROR: Enter search Criteria") : mysql_escape_string($_POST['search']);
$dropdown = empty($_POST['dropdown'])? die ("ERROR: Select from dropdown") : mysql_escape_string($_POST['dropdown']);

// NEEDED TO ADD THESE LINES IN
$search1 = empty($_POST['search1'])? die ("ERROR: Enter search Criteria") : mysql_escape_string($_POST['search1']);
$dropdown1 = empty($_POST['dropdown1'])? die ("ERROR: Select from dropdown") : mysql_escape_string($_POST['dropdown1']);


// Open Connection

$connect = mysql_connect($host, $user, $pass) or die ("Unable to connect to host");

//Select Database

mysql_select_db($db) or die ("Unable to connect to database");

//Create query
// NEEDED TO CHANGE THE AND TO AN OR...
$query = "SELECT * FROM contacts WHERE $dropdown='$search' OR $dropdown1='$search1'" or die (mysql_error());


$result = mysql_query($query) or die (mysql_error());

$num=mysql_numrows($result);

mysql_close($connect);

echo "<b><center>Database Output</center></b><br><br>";

$i=0;
while ($i < $num) {

$first=mysql_result($result,$i,"first");
$last=mysql_result($result,$i,"last");
$company=mysql_result($result,$i,"company");
$address=mysql_result($result,$i,"address");
$town=mysql_result($result,$i,"town");
$city=mysql_result($result,$i,"city");
$postcode=mysql_result($result,$i,"postcode");
$mobile=mysql_result($result,$i,"mobile");
$phone=mysql_result($result,$i,"phone");
$email=mysql_result($result,$i,"email");
$website=mysql_result($result,$i,"website");

echo "<b>$first $last</b><br>Company: $company<br><br>Street Name: $address<br>Town: $town<br>City: $city<br>Postcode: $postcode<br>Mobile: $mobile<br>Phone: $phone<br>Email: $email<br>Website: $website<br><hr><br>";

$i++;

}
}
?>
</body>
</html>

 

Thanks

Karl

Link to comment
Share on other sites
This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
 Share
Go to topic listing
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.