[SOLVED] PHP form checking

[imperialized]

Ok, so I created a form that validates with ajax

 

if an error is encountered, it will return a value.

 

example:

The original code is this:

<tr>

<td width=350>

<b>Email Address:</b><br>

<font size=2>*Email address MUST be valid in order to play.</font>

</td>

<td>

<span id=\"email_chk\">

<input id=\"email\" name=\"email\" type=\"text\" class=\"reg_form\" maxlength=\"80\" onblur=\"check_email(this.form)\">

</span>

</td>

</tr>

 

 

the returned code is this:

print "<input id=\"email\" name=\"email\" type=\"text\" class=\"reg_form\" maxlength=\"80\" style=\"$failed\" value=\"$email\" onblur=\"check_email(this.form)\"> $x <br>

<font size=1.5 color=red>Email does not match!

 

--->  <input type=hidden name=\"email_error\" value=\"1\">

 

sets the error value to 1

 

When I call my javascript:

 

      var email_error=document.registration_form.email_error.value;

if(email_error == 1){

alert('Check your email!');

return false;

}

 

The javascript doesn't catch anything or provide an alert... I dont know javascript for shit so I am lost

[imperialized]

I guess this is solved, the problem was using the same form element name for both password and email fields, so javascript wasnt erroring but couldnt get the values. solved.