ajax's help

[kdhearon]

since i suck at explaining this here is a image to show what i am talking about

 

 

Also would like it like this

 

The site is www.the-leg.net/xcg

 

The ajax.php is

 

<?php

header("Content-Type: text/javascript");

include("_mysql.php");

include("_settings.php");

include("_functions.php");

$get = safe_query("SELECT * FROM ".PREFIX."squads");

?>

squads = new Array();

<?php

$i=1;

while($ds = mysql_fetch_array($get)){

echo "squads[".$i."] = '".$ds['name']."';\n";

$i++;

}

?>

cur = 1;

var max = <?=mysql_num_rows($get);?>;

var http_request = false;

function ajax_request(url) {

if(url<=0) url = max;

if(url>max) url = 1;

cur = url;

url = 'ajax_squads.php?s='+url;

//alert(cur);

http_request = false;

 

if (window.XMLHttpRequest) { // Mozilla, Safari,...

http_request = new XMLHttpRequest();

if (http_request.overrideMimeType) {

http_request.overrideMimeType('text/xml');

// zu dieser Zeile siehe weiter unten

}

} else if (window.ActiveXObject) { // IE

try {

http_request = new ActiveXObject("Msxml2.XMLHTTP");

} catch (e) {

try {

http_request = new ActiveXObject("Microsoft.XMLHTTP");

} catch (e) {}

}

}

 

if (!http_request) {

//$(div).innerHTML = 'Ende  Kann keine XMLHTTP-Instanz erzeugen';

return false;

}

http_request.onreadystatechange = function (){

if (http_request.readyState == 4) {

if (http_request.status == 200) {

//$(div).innerHTML = http_request.responseText;

// $('squad_name').innerHTML = squads[cur];

//alert(http_request.responseText);

} else {

//$(div).innerHTML = 'Bei dem Request ist ein Problem aufgetreten.';

}

}

};

http_request.open('GET', url, true);

http_request.send(null);

 

}

 

 

 

It is just not working right. I cant figure it out. Please help!

 

[kdhearon]

I am welling to pay for some help on this. Or someone to make this script work.