why am i getting problems with this foreach loop

[predator]

hey i got this for each loop

if($_POST['remove']){
foreach($_POST['remove'] as $k=>$v){
mysql_query("DELETE FROM sections WHERE id='$v' LIMIT 1");
}
}

and i am getting the error of

Warning: Invalid argument supplied for foreach()

the $_POST['remove'] is an array i get from an html page and it has a products id assigned to it

but i just cant work out why this is giving me an error.

any help greatly apprechiated

Regards
Mark

[wildteen88]

If you are getitng that error then $_POST['remove'] is not an array. Try this code:
[code=php:0]echo '<pre>' . print_r($_POST['remove'], true) . '</pre>';[/code]

What does that return?

Also if you have input fields that have the same name as remove make sure you have add the square brackets after the name, eg: remove[]

[effigy]

Are you sure it is an array? Make sure it has [] after the name in HTML, and use is_array in PHP to double check.

[predator]

yes it is an array the name of each check box is
remove[{$content[i].id}]

where $content is obviously the id that will be passed into each remove element.

personally i dont like this way of coding however i have taken this project over at work and cant totally re write the code as the customer needs it done obviously sooner than later

regards
Mark

[akitchin]

it would still be nice to see the input's HTML to verify that it isn't a spelling or notation error.