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Counting the number of files in a Zip file.


MilesWilson

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Hello!

Can anyone help me with this? I want to be able to count the number of files in an uploaded zip file.

I have this code:
[code]
<?php
$zip = zip_open("images.zip");
/* At this point I would like to echo another peice of javascript, telling the parent how many files there are in the zip */
if ($zip) {
  while ($zip_entry = zip_read($zip)) {
      if (zip_entry_open($zip, $zip_entry, "r")) {
                $buf = zip_entry_read($zip_entry, zip_entry_filesize($zip_entry));
          $name = zip_entry_name($zip_entry);
$stream = fopen('images/'.$name, "w");
          fwrite($stream, $buf) or die("helllp!");
          zip_entry_close($zip_entry);
echo "<script language='javascript'> window.parent.displayImage('".$name."'); </script>";
ob_flush();
flush();
sleep(3);
      }
  }
  zip_close($zip);
}

?>
[/code]

The sleep(3) is there to replace the code I will write shortly, which resizes the image. In the meantime, sleep() means I get a simulation of the time passing.

Thanks in advance.

Miles
You could do this another way, if the script is running on linux

[code]
$command = "tar -tvf $file > file.output"
system ($command, $output);

$lines = file(file.output);
$num_lines = count ($lines);

echo "The Zip file has $num_lines lines";
[/code]

easy :)
  • 5 months later...
[quote author=vidyashankara link=topic=100577.msg397178#msg397178 date=1152899863]
This works only on tar files, If you want it for a zip file, just use a command to list the files in the zip file in the $command statement instead!

[/quote]

and what exactly would that command be? I'm not fluent with Linux at all.

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