CerealBH Posted February 19, 2009 Share Posted February 19, 2009 does this seem right? $result = mysql_query("SELECT Name FROM johnjrum WHERE Name="$name" LIMIT 1"); if (!$result) { echo 'Could not run query: ' . mysql_error(); exit; } while($row = mysql_fetch_array($result)) { if($row['Name'] == $name) { break out of code already in } else if ($row['Name'] != $name) { Say hi to $name enter $name into database so i dont say hi again } } Quote Link to comment https://forums.phpfreaks.com/topic/145991-solved-phpmysql-logic/ Share on other sites More sharing options...
sasa Posted February 19, 2009 Share Posted February 19, 2009 $result = mysql_query("SELECT Name FROM johnjrum WHERE Name="$name" LIMIT 1"); if (!$result) { echo 'Could not run query: ' . mysql_error(); exit; } if (mysql_num_rows($result) > 0) { Say hi to $name enter $name into database so i dont say hi again } Quote Link to comment https://forums.phpfreaks.com/topic/145991-solved-phpmysql-logic/#findComment-766449 Share on other sites More sharing options...
CerealBH Posted February 19, 2009 Author Share Posted February 19, 2009 thank you works like a charm! Quote Link to comment https://forums.phpfreaks.com/topic/145991-solved-phpmysql-logic/#findComment-766463 Share on other sites More sharing options...
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