[SOLVED] PHP MySql database search code not returning results

[sandbudd]

PHP MySql database search code not returning results and it is throwing no errors and is connecting to the database?

 

<h2>Search</h2>
<form name="search" method="post" action="<?=$PHP_SELF?>">
Seach for: <input type="text" name="find" /> in
<Select NAME="field">
<Option VALUE="state">State</option>
<Option VALUE="lname">Last Name</option>
<Option VALUE="info">Profile</option>
</Select>
<input type="hidden" name="searching" value="yes" />
<input type="submit" name="search" value="Search" />
</form>
<?
//This is only displayed if they have submitted the form
if ($searching =="yes")
{
echo "<h2>Results</h2><p>";

//If they did not enter a search term we give them an error
if ($find == "")
{
echo "<p>You forgot to enter a search term";
exit;
}

// Otherwise we connect to our Database
mysql_connect("", "", "") or die(mysql_error());
mysql_select_db("") or die(mysql_error());

// We preform a bit of filtering
$find = strtoupper($find);
$find = strip_tags($find);
$find = trim ($find);

//Now we search for our search term, in the field the user specified
$data = mysql_query("SELECT * FROM IO#9753#1 WHERE upper($field) LIKE'%$find%'");

//And we display the results
while($result = mysql_fetch_array( $data ))
{
echo $result['state'];
echo " ";
echo $result['lname'];
echo "<br>";
echo $result['info'];
echo "<br>";
echo "<br>";
}

//This counts the number or results - and if there wasn't any it gives them a little message explaining that
$anymatches=mysql_num_rows($data);
if ($anymatches == 0)
{
echo "Sorry, but we can not find an entry to match your query<br><br>";
}

//And we remind them what they searched for
echo "<b>Searched For:</b> " .$find;
}
?> 

[GingerRobot]

In MySQL, the hash (#) comments the rest of the line out. You should consider changing your table name to avoid problems in the future, though you can get around the problem by placing the table name inside backticks (`).

[cunoodle2]

For debugging do the following...

 

$query = "SELECT * FROM IO#9753#1 WHERE upper($field) LIKE'%$find%;";

$data = mysql_query($query);

echo $query;

 

Examine the output to see if something is wrong with the SQL statement. Try running it directly against your database using phpMyAdmin or the command line client.  I'm willing to bet there is an issue with your query.  If not look into the mysql_num_rows and echo out the number of rows and proceed from there.  Echo to the screen is probably one of the fastest ways to troubleshoot an issue.

[sandbudd]

did you want me to put that code in place of this

 

$data = mysql_query("SELECT * FROM IO#9753#1 WHERE upper($field) LIKE'%".$find."%'"

);

[sandbudd]

the backticks worked...thanks