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I want to index each row fetch through mysql database in php. For example, i have a database having two tables Tbl1 and Tbl2. Now i fetch data as an array :

 

$rowTbl1 = mysql_fetch_array($Tbl1result);

$rowTbl2 = mysql_fetch_array($Tbl2result);

 

cnt1Tbl1 = $rowTbl1['cnt'];

cnt1Tbl2 = $rowTbl2['cnt'];

 

I want to compare first row's field 'cnt' with each row on Tbl2 data. How to do that ?

 

e.g. if (cnt1Tbl1 > cnt1Tbl2) {

        // Do something

    }

    else {

      // get 'cnt' of next row from $rowTbl2

      if (cnt1Tbl1 > cnt2Tbl2) {

        // Do something

      }

      else {

          // get 'cnt' of next row from $rowTbl2

          if (cnt1Tbl1 > cnt3Tbl2) {

            // Do something

          }

 

        }

    }

SELECT * FROM `tbl1` JOIN `tbl2` ON (tbl1.cnt > tbl2.cnt) WHERE `whatever` = 'whatever'

 

basically this query will grab every row TO BEGIN WITH which tbl1.cnt is greater than tbl2.cnt

 

then, it will proceed with the WHERE clause on that result set.

I dint understand it exactly...Russell...well, let me elaborate it a bit more...

 

Consider i fetched two arrays $rowTbl1 & $rowTbl2 from mysql database. Assume in both case we got different no. of rows. $rowTbl1 has 10 rows and $rowTbl2 has 15 rows. Now i want to compare each row of $rowTbl1 with each row of $rowTbl2. I want to do something like below :

 

for ($i = 0; $i<10; $i++) {

  for ($j = 0; $j<15; $i++) {

      if ($rowTbl1[$i].cnt > $rowTbl2[$j].cnt) {

        // do something

      }

  }

}

 

I'm not sure how to do it ?

 

ok..

 

<?php
$q1 = mysql_query("SELECT * FROM `tbl1`");
$q2 = mysql_query("SELECT * FROM `tbl2`");
while ($tbl1 = mysql_fetch_assoc($q1)) {
  $t1[] = $tbl1;
}
while ($tbl2 = mysql_fetch_assoc($q1)) {
  $t2[] = $tbl2;
}
$lead = ((count($tbl1) <= count($tbl2))? $tbl1:$tbl2);
$foll = ((count($tbl1) >= count($tbl2))? $tbl1:$tbl2);
for ($i = 0; $i < count($lead); $i++) {
  for ($k = 0; $k < count($foll); $k++) {
    if ($lead[$i]['cnt'] > $foll[$i]['cnt']) {
      do something
    }
  }
}
?>

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