"passing" arrays

[kalivos]

I'm trying to declare two arrays in a function, then call that function from another function. It seems that the second function will not use these arrays. How do I get them to "pass"?

-- Sample code --

[code]function function_a($type)
{
$array_1 = array("Value1", "Value2");
$array_2 = array("Value100", "Value200");

        // following is an attempt to return an array. Incorrect way of doing it?
if($type == "some_value")
{
return $array_1;
}
elseif ($type == "other_value")
{
return $array_2;
}
}

function function_b()
{

        function_a("other_value");
        print_r($array_2);

}
[/code]

Thanks in advance,
-Kalivos

[wildteen88]

Do this instead:
function function_b()
{
    print_r(function_a("other_value"));
}

return does return the variable, $array_2, but the value of $array_2.

[kalivos]

Ahh, works. Thanks!